ltf*_*hie 2 mongodb aggregation-framework spring-data-mongodb
我希望汇总以下数据
{
"user": "user1",
"error": true
}
{
"user": "user2",
"error": false
}
{
"user": "user1",
"error": false
}
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成
{
"_id": "user1",
"errorCount": 1,
"totalCount": 2
},
{
"_id": "user2",
"errorCount": 0,
"totalCount": 1
}
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使用$ cond运算符,可以使用以下方法实现:
$group: {
_id: "$user",
errorCount : { "$sum" : {"$cond" : ["$error", 1, 0]}},
totalCount : { "$sum" : 1 }
}
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但是,由于我使用的是Spring-data-mongodb,它还不支持$ cond(从1.3.4-RELEASE开始),我无法做到这一点.
有没有办法在没有$ cond的情况下进行相同的聚合?
感谢Neil Lunn的建议,我设法让$ cond使用spring-data的聚合支持.为此,您必须实现AggregationOperation接口以接收DBObject.
public class DBObjectAggregationOperation implements AggregationOperation {
private DBObject operation;
public DBObjectAggregationOperation (DBObject operation) {
this.operation = operation;
}
@Override
public DBObject toDBObject(AggregationOperationContext context) {
return context.getMappedObject(operation);
}
}
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然后你就可以在TypeAggregation中正常使用它了:
DBObject operation = (DBObject)JSON.parse ("your pipleline here...");
TypedAggregation<UserStats> aggregation = newAggregation(User.class,
new DBObjectAggregationOperation(operation)
);
AggregationResults<UserStats> result = mongoTemplate.aggregate(aggregation, UserStats.class);
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此方法将允许您使用框架中尚未定义的任何聚合运算符.但是,它也绕过了弹簧数据的验证,应谨慎使用.
如果您希望通过该框架正确支持$ cond运算符,请投票:https://jira.springsource.org/browse/DATAMONGO-861
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