Automapper自定义解析器

Question

对于我这个简单的问题,我很抱歉,但我无法让它发挥作用.我的问题:我想从域对象映射到模型对象但是,在域对象中我有一个列表,所以我的对象看起来像:

public class Conference
 {
   public virtual  int Id{get;set;}
   public virtual int  NumberOfTables{get;set;}
   public virtual IList<People> Peoples{get;set;}
 }

public class People
 {
   public virtual  int Id{get;set;}
   public virtual string FirstName{get;set;}
   public virtual string LastName{get;set;}
   public virtual  Conference Conference{get;set;}
 }

My model :


public class Model
{
  public int Id{get;set;}
  public int NumberOfTables{get;set;}
  public string Peoples{get;set;}
}

我希望人们像:"FirstName"+"LastName"+","对于列表中的所有人现在从Domain Obj到Model的映射我有这样的事情:

Mapper.CreateMap<Conference,Model>()
     .ForMember(c => c.Id, op => op.MapFrom(v => v.Id))
     .ForMember(c => c.NumberOfTables, op => op.MapFrom(v => v.NumberOfTables))
      .ForMember(c => c.Peoples, op => op//here I want to use ResolveUsing or something like this  )



  public class CustomConvert: ValueResolver<IList<GroupOfComponentInComplexToMeal>, string>
    {
        protected override string ResolveCore(IList<People> source)
        {
            string result = "";
            if (source.Any())
            {
                for (int i = 0; i < source.Count; i++)
                {
                    var name=source[i].FirstName+source[i].LastName;
                    result += name;
                    if (i < source.Count - 1)
                    {
                        result += ",";
                    }
                }
            }
            return result;
        }
    }

我做了这个CustomConvert,但我不能将它与我的mapper合并.

如果我需要使用自定义转换器,我现在真的不知道,但我想了解它们是如何工作的.任何帮助将不胜感激.

Answer 1

让它工作非常简单,但我仍然需要一些很好的例子来了解有关自定义解析器的更多信息.

解:

Mapper.CreateMap<Conference,Model>()
    .ForMember(c => c.Id, op => op.MapFrom(v => v.Id))
    .ForMember(c => c.NumberOfTables, op => op.MapFrom(v => v.NumberOfTables))
    .ForMember(c => 
        c.Peoples, op => op.ResolveUsing<CustomConvert>().FromMember(x => x.Peoples)
    );