反向C风格的字符串? - C++

Ale*_*lex 3 c++ arrays pointers

我想使用指针来反转C++中的char数组.我想知道是否有什么我应该采取不同的做法?我这样做了吗?有没有更有效的方法来实现这一目标?

我的小程序:

int main ( )
{
    char buffer[80];

    PrintHeader();

    cout << "\nString reversal program";
    cout << "\nType in a short string of words.";
    cout << "\nI will reverse them.";
    cout << "\n:";
    cin.getline(buffer, 79);

    cout << "\nYou typed " << buffer;
    reverse (buffer);
    cout << "\nReversed: " << buffer;

    cout << endl;
    system("PAUSE");
    return 0;

}


void reverse(char* string)
{
    char* pStart, *pEnd;
    int length;
    char temp;

    length = strlen(string);

    pStart = string;
    pEnd = &string[length - 1];

    while(pStart < pEnd)
    {
        temp = *pStart;
        *pStart = *pEnd;
        *pEnd = temp;
        pStart++;
        pEnd--;
    }
}
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Pot*_*ter 9

void str_reverse( char *str ) {
    char *str_end = strchr( str, 0 );
    std::reverse( str, str_end );
}
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如果你应该写一个循环,

void str_reverse( char *str ) {
    std::size_t len = std::strlen( str );
    for ( std::size_t index = 0; index != len / 2; ++ index ) {
        std::swap( str[ index ], str[ len - index - 1 ] );
    }
}
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或者,当然,如果你可以使用C++字符串,

void str_reverse( std::string &str ) {
    std::reverse( str.begin(), str.end() );
}
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