响应代码304和200时的排球异常错误

Question

玩弄Volley库时,我注意到在进行POST时JsonObjectRequest,如果服务器返回代码304或200且响应中没有数据,则(response.data)Volley将其解释为错误响应,而不是成功.

我设法通过Response<JSONObject> parseNetworkResponse(NetworkResponse response)在类中的方法中添加几行代码来解决它JsonObjectRequest.java.

@Override
protected Response<JSONObject> parseNetworkResponse(NetworkResponse response) {
    try {
        if (!response.notModified) {// Added for 304 response
            String jsonString = new String(response.data,
                    HttpHeaderParser.parseCharset(response.headers));
            return Response.success(new JSONObject(jsonString),
                    HttpHeaderParser.parseCacheHeaders(response));
        } else // Added for 304 response
            return Response.success(new JSONObject(),HttpHeaderParser.parseCacheHeaders(response));
    } catch (UnsupportedEncodingException e) {
        Log.v("Volley", "UnsupportedEncodingException " + response.statusCode);
        if (response.statusCode == 200)// Added for 200 response
            return Response.success(new JSONObject(), HttpHeaderParser.parseCacheHeaders(response));
        else
            return Response.error(new ParseError(e));
    } catch (JSONException je) {
        Log.v("Volley", "JSONException " + response.statusCode);
        if (response.statusCode == 200)// Added for 200 response
            return Response.success(new JSONObject(),HttpHeaderParser.parseCacheHeaders(response));
        else
            return Response.error(new ParseError(je));
    }
}

这是解决这个问题的最佳方法吗？

谢谢!

编辑

检查课程BasicNetwork.java我意识到Volley通过询问是否检查响应是否没有数据httpResponse.getEntity() != null.

// Some responses such as 204s do not have content. We must check.
    if (httpResponse.getEntity() != null) {
        responseContents = entityToBytes(httpResponse.getEntity());         
    } else {// Add 0 byte response as a way of honestly representing a
    // no-content request.
        responseContents = new byte[0];
    }

但问题仍然是Volley尝试response.data == new byte[0]在parseNetworkResponse方法中创建新字符串时发生的JSONException.

Answer 1

Miguel-只有在成功响应的情况下才会调用此方法吗？

对于所有状态代码<200或状态代码> 200,volley调用parseNetworkError(VolleyError volleyError)而不是parseNetworkResponse(NetworkResponse response)方法.看这里 -

https://android.googlesource.com/platform/frameworks/volley/+/master/src/com/android/volley/toolbox/BasicNetwork.java

行号-118-120

  if (statusCode < 200 || statusCode > 299) {
                throw new IOException();
   }

和相应的catch块行号 - 128 -151

catch (IOException e) {
            int statusCode = 0;
            NetworkResponse networkResponse = null;
            if (httpResponse != null) {
                statusCode = httpResponse.getStatusLine().getStatusCode();
            } else {
                throw new NoConnectionError(e);
            }
            VolleyLog.e("Unexpected response code %d for %s", statusCode, request.getUrl());
            if (responseContents != null) {
                networkResponse = new NetworkResponse(statusCode, responseContents,
                        responseHeaders, false);
                if (statusCode == HttpStatus.SC_UNAUTHORIZED ||
                        statusCode == HttpStatus.SC_FORBIDDEN) {
                    attemptRetryOnException("auth",
                            request, new AuthFailureError(networkResponse));
                } else {
                    // TODO: Only throw ServerError for 5xx status codes.
                    throw new ServerError(networkResponse);
                }
            } else {
                throw new NetworkError(networkResponse);
            }
        }

如果要覆盖此行为,可以在BasicNetwork.java-> performRequest方法中添加特定于状态代码的实现.

编辑:所以它不是因为状态代码而是因为空响应.好吧,我认为你正在做正确的事情来实现你的自定义Request类.Volley附带了一些易于使用的预定义流行类型请求,但您可以随时创建自己的.而不是基于状态代码的实现,我宁愿在反序列化之前检查以下字符串是否为空 -

String jsonString = new String(response.data,
                HttpHeaderParser.parseCharset(response.headers));
if (!jsonString .isEmpty()) {
                 return Response.success(new JSONObject(jsonString),
                HttpHeaderParser.parseCacheHeaders(response));
}
else {
return Response.success(new JSONObject(),
                    HttpHeaderParser.parseCacheHeaders(response));
}

**没有测试过这个,但你明白了:)