使用spring restTemplate进行REST API的基本身份验证

shi*_*ppi 67 java spring resttemplate jira-rest-api

我在RestTemplate中是全新的,基本上也在REST API中.我想通过Jira REST API在我的应用程序中检索一些数据,但是要取回401 Unauthorized.找到并发表关于jira rest api文档的文章,但实际上并不知道如何将其重写为java,因为该示例使用curl命令行方式.我将不胜感激任何建议或建议如何重写:

curl -D- -X GET -H "Authorization: Basic ZnJlZDpmcmVk" -H "Content-Type: application/json" "http://kelpie9:8081/rest/api/2/issue/QA-31"
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使用spring rest模板进入java.其中ZnJlZDpmcmVk是base64编码的username:password字符串.非常感谢你.

Ang*_*ity 125

本网站上示例中,我认为这将是最自然的方式,通过填写标头值并将标头传递给模板.

这是填写标题Authorization:

String plainCreds = "willie:p@ssword";
byte[] plainCredsBytes = plainCreds.getBytes();
byte[] base64CredsBytes = Base64.encodeBase64(plainCredsBytes);
String base64Creds = new String(base64CredsBytes);

HttpHeaders headers = new HttpHeaders();
headers.add("Authorization", "Basic " + base64Creds);
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这是将标头传递给REST模板:

HttpEntity<String> request = new HttpEntity<String>(headers);
ResponseEntity<Account> response = restTemplate.exchange(url, HttpMethod.GET, request, Account.class);
Account account = response.getBody();
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  • java 8你可以使用Base64.getMimeEncoder().encodeToString() (7认同)
  • 谢谢-这对我有用。我必须指出,如果您不想使用 org.apache.commons.codec.binary.Base64 类,并且想使用 android Base64 类: import android.util.Base64; ,您可以替换上面一行: byte[] base64CredsBytes = Base64.encode(plainCredsBytes, Base64.DEFAULT); (2认同)

Ale*_*lex 69

您可以使用spring-boot RestTemplateBuilder

@Bean
RestOperations rest(RestTemplateBuilder restTemplateBuilder) {
    return restTemplateBuilder.basicAuthentication("user", "password").build();
}
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文档

(在SB 2.1.0之前#basicAuthorization)

  • 谢谢!这是最快速,最简单的方法. (3认同)
  • @ 2.1.0起不推荐使用#basicAuthentication(字符串用户名,字符串密码) (3认同)
  • 这不是一个好的解决方案,因为它会为通过“RestTemplate”发送的每个请求添加授权标头。 (3认同)

att*_*ian 23

有多种方法可以将基本 HTTP 身份验证添加到RestTemplate.

1. 对于单个请求

try {
    // request url
    String url = "https://jsonplaceholder.typicode.com/posts";

    // create auth credentials
    String authStr = "username:password";
    String base64Creds = Base64.getEncoder().encodeToString(authStr.getBytes());

    // create headers
    HttpHeaders headers = new HttpHeaders();
    headers.add("Authorization", "Basic " + base64Creds);

    // create request
    HttpEntity request = new HttpEntity(headers);

    // make a request
    ResponseEntity<String> response = new RestTemplate().exchange(url, HttpMethod.GET, request, String.class);

    // get JSON response
    String json = response.getBody();

} catch (Exception ex) {
    ex.printStackTrace();
}
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如果您使用的是 Spring5.1或更高版本,则不再需要手动设置授权标头。改用headers.setBasicAuth()方法:

// create headers
HttpHeaders headers = new HttpHeaders();
headers.setBasicAuth("username", "password");
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2.对于一组请求

@Service
public class RestService {

    private final RestTemplate restTemplate;

    public RestService(RestTemplateBuilder restTemplateBuilder) {
        this.restTemplate = restTemplateBuilder
                .basicAuthentication("username", "password")
                .build();
    }

   // use `restTemplate` instance here
}
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3. 对于每一个请求

@Bean
RestOperations restTemplateBuilder(RestTemplateBuilder restTemplateBuilder) {
    return restTemplateBuilder.basicAuthentication("username", "password").build();
}
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我希望它有帮助!


Leo*_*eon 20

(也许)没有导入spring-boot的最简单方法.

restTemplate.getInterceptors().add(new BasicAuthorizationInterceptor("user", "password"));
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  • 请注意,使用拦截器会导致流不再有效。原因如下:`exchange()` -&gt; `doExecute()`,-&gt; `createRequest()`,-&gt; `InterceptingHttpAccessor.getRequestFactory()`(因为`RestTemplate` 扩展了`InterceptingHttpAccessor`)。如果有拦截器,`getRequestFactory()` 返回一个`InterceptingClientHttpRequestFactory`,它创建`InterceptingClientHttpRequest`s。这些扩展了 AbstractBufferingClientHttpRequest`,它将输入流转换为 byte[](移交给拦截器)。因此, InputStream 实际上并未流式传输。 (4认同)
  • 这种方法现已被弃用。请改用 BasicAuthenticationInterceptor。 (2认同)

Joh*_*Lim 17

参考Spring Boot的TestRestTemplate实现如下:

https://github.com/spring-projects/spring-boot/blob/master/spring-boot/src/main/java/org/springframework/boot/test/TestRestTemplate.java

特别是,请参阅addAuthentication()方法,如下所示:

private void addAuthentication(String username, String password) {
    if (username == null) {
        return;
    }
    List<ClientHttpRequestInterceptor> interceptors = Collections
            .<ClientHttpRequestInterceptor> singletonList(new BasicAuthorizationInterceptor(
                    username, password));
    setRequestFactory(new InterceptingClientHttpRequestFactory(getRequestFactory(),
            interceptors));
}
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同样,您可以RestTemplate轻松制作自己的

通过继承TestRestTemplate如下:

https://github.com/izeye/samples-spring-boot-branches/blob/rest-and-actuator-with-security/src/main/java/samples/springboot/util/BasicAuthRestTemplate.java


小智 12

从Spring 5.1开始,您可以使用 HttpHeaders.setBasicAuth

创建基本授权标头:

String username = "willie";
String password = ":p@ssword";
HttpHeaders headers = new HttpHeaders();
headers.setBasicAuth(username, password);
...other headers goes here...
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将标题传递给RestTemplate:

HttpEntity<String> request = new HttpEntity<String>(headers);
ResponseEntity<Account> response = restTemplate.exchange(url, HttpMethod.GET, request, Account.class);
Account account = response.getBody();
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文档:https : //docs.spring.io/spring-framework/docs/current/javadoc-api/org/springframework/http/HttpHeaders.html#setBasicAuth-java.lang.String-java.lang.String-


小智 6

而不是实例化如下:

TestRestTemplate restTemplate = new TestRestTemplate();
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就这样做:

TestRestTemplate restTemplate = new TestRestTemplate(user, password);
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它对我有用,我希望它有所帮助!

  • 这不是应该用于单元测试而不是发布代码吗? (2认同)