拆分一个字符串并将子字符串保存到dict.蟒蛇

Question

我有这样的文本文件:

771 776 #1 556.766700(2)
538 #2 1069.652700(2)
531 #3 1074.407600(2)
81 84 89 94 111 #4 1501.062900(2)
85 91 #5 782.298900(3)
32 42 66 71 90 95 101 #6 904.016500(3)

我想分割并将子串保存到不同的变量,如下所示:例如在第1行:

scans= 771 776, uid = 1 mz = 556.766700, z = 2

我正在尝试使用以下代码,但我需要有关正则表达式的帮助:

f = open(filename, 'r')
par_info=[]
for rows in f:
    re.sub('\#(.+)\s(.+)\((.+)\+', scans=\g<1>, uid=\g<2>, mz = int(\g<3>),    z=int(\g<4>), rest)
    info={'sc_num':scans, 'ident':uid, 'mass':mz, 'charge':z}
    par_info.append(info)

Answer 1

您可以使用命名组:

>>> import pprint
>>> import re
>>> r = re.compile(r'(?P<scans>.*?)\s+#(?P<uid>\d+)\s+(?P<mz>\d+\.\d+)\((?P<z>\d+)\)')
>>> with open('abc1') as f:
        par_info = [r.search(line).groupdict() for line in f]
...     
>>> pprint.pprint(par_info)
[{'mz': '556.766700', 'scans': '771 776', 'uid': '1', 'z': '2'},
 {'mz': '1069.652700', 'scans': '538', 'uid': '2', 'z': '2'},
 {'mz': '1074.407600', 'scans': '531', 'uid': '3', 'z': '2'},
 {'mz': '1501.062900', 'scans': '81 84 89 94 111', 'uid': '4', 'z': '2'},
 {'mz': '782.298900', 'scans': '85 91', 'uid': '5', 'z': '3'},
 {'mz': '904.016500', 'scans': '32 42 66 71 90 95 101', 'uid': '6', 'z': '3'}]