我用我的数据做了类似的事情,但是尽管透明度很高,但很难看到这些片段(我的数据的片段数比下面的例子少得多)才能看到它们的开头和结尾.
require(ggplot2)
ggplot(iris, aes(x = Petal.Length, xend = Petal.Width,
y = factor(Species), yend = factor(Species),
size = Sepal.Length)) +
geom_segment(alpha = 0.05) +
geom_point(aes(shape = Species))
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碰到这个解决方案,但线条交叉.有没有办法让抖动产生与尖端点的平行线?我试过position_dodge而不是position_jitter,但它需要ymax.可以ymax集成在一起使用geom_segment吗?
ggplot(iris, aes(x = Petal.Length, xend = Petal.Width,
y = factor(Species), yend = factor(Species))) +
geom_segment(position = position_jitter(height = 0.25))+
geom_point(aes(size = Sepal.Length, shape = Species))
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San*_*att 10
据我所知,geom_segment不允许抖动或躲闪.您可以将抖动添加到数据框中的相关变量,然后绘制抖动变量.在您的示例中,因子将转换为数字,然后使用因子将因子级别的标签添加到轴scale_y_continuous.
library(ggplot2)
iris$JitterSpecies <- ave(as.numeric(iris$Species), iris$Species,
FUN = function(x) x + rnorm(length(x), sd = .1))
ggplot(iris, aes(x = Petal.Length, xend = Petal.Width,
y = JitterSpecies, yend = JitterSpecies)) +
geom_segment()+
geom_point(aes(size=Sepal.Length, shape=Species)) +
scale_y_continuous("Species", breaks = c(1,2,3), labels = levels(iris$Species))
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但它似乎geom_linerange允许躲避.
ggplot(iris, aes(y = Petal.Length, ymin = Petal.Width,
x = Species, ymax = Petal.Length, group = row.names(iris))) +
geom_point(position = position_dodge(.5)) +
geom_linerange(position = position_dodge(.5)) +
coord_flip()
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