Tre*_*ung 5 sql postgresql recursive-query common-table-expression
在PostgreSQL中,另一个WITH可以使用WITH,例如:
WITH num AS (
VALUES (50)
), num2 AS (
SELECT column1 * 2 AS value FROM num
)
SELECT value FROM num2;
Run Code Online (Sandbox Code Playgroud)
还有RECURSIVE WITHs,可以这样做:
WITH RECURSIVE t(n) AS (
VALUES (1)
UNION ALL
SELECT n+1 FROM t WHERE n < 100
)
SELECT sum(n) FROM t;
Run Code Online (Sandbox Code Playgroud)
但到目前为止,我还没有找到一种方法让RECURSIVE WITH使用之前的WITH.我认为它应该是这样的:
WITH num AS (
VALUES (50)
), num2 AS (
SELECT column1 * 2 AS value FROM num
), RECURSIVE t(n) AS (
VALUES (1)
UNION ALL
SELECT n+1 FROM t WHERE n < (SELECT * FROM num2)
)
SELECT sum(n) FROM t;
Run Code Online (Sandbox Code Playgroud)
但这不起作用.有没有办法做到这一点?如果是这样,怎么样?
Erw*_*ter 10
从开始WITH RECURSIVE.您仍然可以在递归部分之前挤入"常规"CTE:
WITH RECURSIVE
num AS (VALUES (50))
, num2 AS (SELECT column1 * 2 AS value FROM num)
, t(n) AS (
VALUES (1)
UNION ALL
SELECT n+1 FROM t WHERE n < (SELECT * FROM num2)
)
SELECT sum(n) FROM t;
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
1375 次 |
| 最近记录: |