如何从HttpRequest.postFormData的catchError的_XMLHttpRequestProgressEvent中获取HTTP响应文本？

Question

给出以下伪代码:

import "dart:html";

HttpRequest.postFormData(url, data).then((HttpRequest request) {

    ...

}).catchError((error) {

    // How do I get the response text from here?

});

如果Web服务器回复a 400 BAD REQUEST,catchError则将调用.但是,error参数的类型_XMLHttpRequestProgressEvent在Dart库中显然不存在.

那么,如何400 BAD REQUEST从Web服务器发送的响应中获取响应文本？

Answer 1

看起来你的错误对象中的目标实际上就是你的HttpRequest.

您可能会发现此链接很有用:https://www.dartlang.org/docs/tutorials/forms/#handling-post-requests

你可以这样做:

import "dart:html";

HttpRequest.postFormData(url, data).then((HttpRequest request) {
    request.onReadyStateChange.listen((response) => /* do sth with response */);
}).catchError((error) {
    print(error.target.responseText); // Current target should be you HttpRequest
});