我一直在尝试解决这个程序,它接受两个字符串作为输入并输出常用字母数.例如,如果输入是"common"和"connor",则输出应为4(1 c,1 n和2 o).我使用set()函数但输出3(它将两个o视为单个公共信件 ).任何帮助将不胜感激.谢谢!
顺便说一下这是我写的代码:
print("Enter number of inputs: ")
c = int(input())
store = []
for each_item in range(c):
print("Enter First String: ")
one = input()
print("Enter Second String")
two = input()
s = len(set(one) & set(two))
store.append(s)
for each_number in store:
print(each_number)
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>>> from collections import Counter
>>> Counter('common')
Counter({'m': 2, 'o': 2, 'c': 1, 'n': 1})
>>> Counter('connor')
Counter({'o': 2, 'n': 2, 'c': 1, 'r': 1})
>>> common = Counter('common') & Counter('connor') # intersection
>>> common
Counter({'o': 2, 'c': 1, 'n': 1})
>>> sum(common.values())
4
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