我正在阅读Beejs的网络编程指南
我很难理解链表的目的,即这个结构中的最终参数:
struct addrinfo {
int ai_flags; // AI_PASSIVE, AI_CANONNAME, etc.
int ai_family; // AF_INET, AF_INET6, AF_UNSPEC
int ai_socktype; // SOCK_STREAM, SOCK_DGRAM
int ai_protocol; // use 0 for "any"
size_t ai_addrlen; // size of ai_addr in bytes
struct sockaddr *ai_addr; // struct sockaddr_in or _in6
char *ai_canonname; // full canonical hostname
struct addrinfo *ai_next; // linked list, next node
};
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这有什么需要?下一个节点是指下一个客户端还是什么?
主机可以拥有多个IP地址.例如,IPv4和IPv6地址,或多个IPv4地址.因此,getaddrinfo()为您提供指向一个或多个addrinfo结构的链接列表ai_next的指针,并且是指向下一个元素或NULL列表中最后一个元素的指针.
示例(打印主机的所有IP地址):
struct addrinfo hints;
memset(&hints, 0, sizeof(hints));
hints.ai_family = PF_UNSPEC;
hints.ai_protocol = IPPROTO_TCP;
struct addrinfo *addrs, *addr;
getaddrinfo("www.google.com", NULL, &hints, &addrs);
// addrs points to first addrinfo structure.
// Traverse the linked list:
for (addr = addrs; addr != NULL; addr = addr->ai_next) {
char host[NI_MAXHOST];
getnameinfo(addr->ai_addr, addr->ai_addrlen, host, sizeof(host), NULL, 0, NI_NUMERICHOST);
printf("%s\n", host);
}
freeaddrinfo(addrs);
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(为简洁起见,省略了错误检查.)