mysql timediff到几个小时

Question

我正试图从我的桌子上获取timediff并将其转换为几小时(这是一个小时计费服务)

SELECT TIME_TO_SEC(TIMEDIFF(endDate,startDate))/ 3600 FROM tasks>

其中endDate和startDate采用日期时间格式

还有另一种方法(更有效率)来完成这项任务吗？谢谢 !

Answer 1

TIMEDIFF(endDate, startDate) DateTime格式的输出,如此平坦,以时间戳和devide(60*60)

SELECT (UNIX_TIMESTAMP(TIMEDIFF(endDate, startDate))/(60*60)) AS hours_difference
FROM tasks

编辑:或者, TimestampDiff也可以更优雅的方式提供有效的解决方案,提供其示例:

SELECT TIMESTAMPDIFF(MONTH,'2003-02-01','2003-05-01');

您的解决方案可以是:

SELECT TIMESTAMPDIFF(HOUR, startDate, endDate) AS hours_different
FROM tasks

Answer 2

注意这个链中投票最多的答案是不正确的!使用HOUR只会返回整数小时.下面将纠正最常见的答案,以小时为单位返回小时(小时为6.5小时).

TIME_TO_SEC(TIMEDIFF(endDate, startDate))/3600 as hours

Answer 3

HOUR(TIMEDIFF(endDate, startDate))

可能有用 - 如果我正确地阅读文档.

Answer 4

TIMESTAMPDIFF(HOUR, startDate, endDate)

是最好的方法,因为它适用于很长的时间间隔,比如

TIMESTAMPDIFF(HOUR, "2012-01-01 00:00:00", "2050-01-01 00:00:00")

结果: 333120

而

HOUR(TIMEDIFF("2050-01-01 00:00:00", "2012-01-01 00:00:00"))

结果: 838

失败.

正如我们在上面的例子中看到的那样,它甚至超出了2038年的时间戳限制.

返回的最大小时数HOUR(TIMEDIFF(dateEnd, dateStart))是838,因为TIMEDIFF它限制在允许的TIME值范围内.

Answer 5

您可以使用UNIX_TIMESTAMP在SELECT查询中进行计算.

SELECT (UNIX_TIMESTAMP(endDate)-UNIX_TIMESTAMP(startDate))/3600 hour_diff
  FROM tasks

UNIX_TIMESTAMP将datetime转换为epoch的秒数.您可以减去两个时间戳以获得第二个差异.用3600除以它会给你不同的小时.

Answer 6

例如:startDate 2010-01-31 00:00:00,endDate 2010-01-31 19:24:22

SELECT (UNIX_TIMESTAMP(dateFin)-UNIX_TIMESTAMP(dateDebut))/3600 hour_diff
FROM tasks

SELECT TIME_TO_SEC(TIMEDIFF(endDate,startDate))/3600
FROM tasks 

返回19.4061,这很好

SELECT TIMESTAMPDIFF(HOUR, endDate, startDate) AS hours_different
FROM tasks

只返回几小时,我还需要转换分钟.

SELECT (UNIX_TIMESTAMP(TIMEDIFF(endDate, startDate))/(60*60)) AS hours_difference
FROM tasks

返回0.我认为第一个是最有效的.谢谢 !!

Answer 7

在小时内获得差异:

Hour(TIMEDIFF(date1,date2)) as Hour1

在分钟中获得差异:

Minute(TIMEDIFF(date1,date2)) as Minute1

获得第二个差异:

Second(TIMEDIFF(date1,date2)) as Second1