Apache异步HttpClient不快

Question

我是Apache http客户端的新手,我正试图从网站获取状态代码.在Apache http教程中找到以下示例.

import java.util.concurrent.CountDownLatch;
import org.apache.http.HttpResponse;
import org.apache.http.client.config.RequestConfig;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.concurrent.FutureCallback;
import org.apache.http.impl.nio.client.CloseableHttpAsyncClient;
import org.apache.http.impl.nio.client.HttpAsyncClients;
public class Abc {
    static long d2;
    public static void main(final String[] args) throws Exception {
        d2=System.currentTimeMillis();
        RequestConfig requestConfig = RequestConfig.custom()
            .setSocketTimeout(3000)
            .setConnectTimeout(3000).build();
        CloseableHttpAsyncClient httpclient = HttpAsyncClients.custom()
            .setDefaultRequestConfig(requestConfig)
            .build();
        try {
            httpclient.start();
            final HttpGet[] requests = new HttpGet[] {
                    new HttpGet("http://192.168.26.175:8080/examples/eye/abc10000.jsp")
            };
            final CountDownLatch latch = new CountDownLatch(1);
            for (int v=0;v<1000;v++) {
                httpclient.execute(requests[0], new FutureCallback<HttpResponse>() {

                    public void completed(final HttpResponse response) {
                        latch.countDown();
                        System.out.println(requests[0].getRequestLine() + "->" + response.getStatusLine());
                    }

                    public void failed(final Exception ex) {
                        latch.countDown();
                        System.out.println(requests[0].getRequestLine() + "->" + ex);
                    }

                    public void cancelled() {
                        latch.countDown();
                        System.out.println(requests[0].getRequestLine() + " cancelled");
                    }

                });
            }
            latch.await();
            System.out.println("Shutting down");
        } finally {
            httpclient.close();
        }
        System.out.println("Done");
      long  d1=System.currentTimeMillis();
      System.out.println(d1-d2);
    }

}

它是真的异步还是串行调用.必须采取哪些措施才能使调用异步且速度更快.

Answer 1

由于请求将在必须进行更改后通过相同的路径.

CloseableHttpAsyncClient httpclient = HttpAsyncClients.custom()
            .setDefaultRequestConfig(requestConfig)
            .setMaxConnPerRoute(1000)
            .setMaxConnTotal(1000)
            .build();

Answer 2

首先也是最重要的：CloseableHttpAsyncClient实例非常昂贵。请不要不创建一个新CloseableHttpAsyncClient的每一个请求。就像为每次链接点击创建一个新的浏览器进程一样，完全是浪费而且非常慢。强烈建议在CloseableHttpAsyncClient逻辑组件的整个生命周期内使用相同的实例。

几乎在所有情况下，阻塞客户端可能比非阻塞（基于 NIO）客户端快得多（只要并发请求的数量低于 1000）。除非您正在构建某种代理，否则阻塞 HTTP 客户端（例如 Apache HttpClient）可能会更好地为您提供服务。