snu*_*kon 7 javascript clojure clojurescript
我最近开始使用ClojureScript.当我将JavaScript程序重写为ClojureScript时,我担心ClojureScript的性能.
ClojureScript代码
(def NUM 10000)
(def data
(vec (repeatedly NUM #(hash-map :x (rand) :y (rand)))))
(.time js/console "cljs")
(loop [x 0 y 0 d data]
(if (empty? d)
[x y]
(recur (+ x (:x (first d)))
(+ y (:y (first d)))
(rest d))))
(.timeEnd js/console "cljs")
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编译的JavaScript代码(优化:空白)
benchmark_cljs.benchmark.NUM = 1E4;
benchmark_cljs.benchmark.data = cljs.core.vec.call(null, cljs.core.repeatedly.call(null, benchmark_cljs.benchmark.NUM, function() {
return cljs.core.PersistentHashMap.fromArrays.call(null, [new cljs.core.Keyword(null, "x", "x", 1013904362), new cljs.core.Keyword(null , "y", "y", 1013904363)], [cljs.core.rand.call(null), cljs.core.rand.call(null)]);
}));
console.time("cljs");
var x_4753 = 0;
var y_4754 = 0;
var d_4755 = benchmark_cljs.benchmark.data;
while (true) {
if (cljs.core.empty_QMARK_.call(null, d_4755)) {
new cljs.core.PersistentVector(null, 2, 5, cljs.core.PersistentVector.EMPTY_NODE, [x_4753, y_4754], null);
} else {
var G__4756 = x_4753 + (new cljs.core.Keyword(null, "x", "x", 1013904362)).cljs$core$IFn$_invoke$arity$1(cljs.core.first.call(null, d _4755));
var G__4757 = y_4754 + (new cljs.core.Keyword(null, "y", "y", 1013904363)).cljs$core$IFn$_invoke$arity$1(cljs.core.first.call(null, d _4755));
var G__4758 = cljs.core.rest.call(null, d_4755);
x_4753 = G__4756;
y_4754 = G__4757;
d_4755 = G__4758;
continue;
}
break;
}
console.timeEnd("cljs");
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JavaScript代码
var NUM = 10000;
var data = [];
for (var i = 0; i < NUM; i++) {
data[i] = {
x: Math.random(),
y: Math.random()
}
}
console.time('js');
var x = 0;
var y = 0;
for (var i = 0; i < data.length; i++) {
x += data[i].x;
y += data[i].y;
}
console.timeEnd('js');
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ClojureScript代码和JavaScrpt代码执行相同的操作,但每个处理时间都不同.
处理时间
ClojureScript(optimizations :whitespace): 30 ? 70ms
ClojureScript(optimizations :advanced): 9 ? 13ms
JavaScript: 0.3ms ? 0.9ms
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请告诉我如何改善ClojureScript的处理时间.
提前致谢.
Mic*_*zyk 13
您在ClojureScript中使用持久性数据结构,在JavaScript中使用可变数组和对象.可以预期两个片段的性能特征将是不同的.
现在,如果性能对您正在做的事情非常重要,并且持久性没有任何好处,您可以使用ClojureScript中的数组和对象:
(def NUM 10000)
(def data (array))
(loop [i 0]
(when (< i NUM)
(aset data i (js-obj "x" (js/Math.random) "y" (js/Math.random)))
(recur (inc i))))
(let [lim (alength data)]
(loop [x 0 y 0 i 0]
(if (< i lim)
(recur (+ x (aget data i "x"))
(+ y (aget data i "y"))
(inc i))
(println x y))))
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另一方面,如果你确实需要坚持所涉及的数据结构的旧版本,你可能会因为不必制作完整的副本来保存它们而赢回"失去的时间".
小智 6
根据您需要多少性能以及您愿意放弃的内容,这里有多种选择.如果你有兴趣,我会在GitHub上放一些基准测试.
通过使用记录和本机字段访问,您可以将原始ClojureScript解决方案的运行时间减半:
(defrecord XY [x y])
(def data (mapv (fn [_] (XY. (rand) (rand))) (range NUM)))
(defn sumXsAndYsWithLoopAndNativeFieldAccess [data]
(loop [x 0 y 0 data data]
(if (seq data)
(let [o (first data)]
(recur (+ x (.-x o)) (+ y (.-y o)) (rest data)))
[x y])))
(time (sumXsAndYsWithLoopAndNativeFieldAccess data))
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您还可以将数组用作可变本地,并获得解决方案的速度仅为本机JavaScript版本的8倍:
(defn sumsXsAndYsWithDotimesNativeFieldAccessAndMutableLocals [data]
(let [x (doto (make-array 1)
(aset 0 0))
y (doto (make-array 1)
(aset 0 0))]
(dotimes [i (count data)]
(let [o (data i)]
(aset x 0 (+ (aget x 0) (.-x o)))
(aset y 0 (+ (aget y 0) (.-y o)))))
[(aget x 0) (aget y 0)]))
(time (sumsXsAndYsWithDotimesNativeFieldAccessAndMutableLocals data))
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此外,您可以将上述内容与数组结合使用,并获得大约是本机JavaScript版本的3倍的解决方案:
(def data (into-array (mapv #(XY. (rand) (rand)) (range NUM))))
(defn sumsXsAndYsWithDotimesOnArrayNativeFieldAccessAndMutableLocals [data]
(let [x (doto (make-array 1)
(aset 0 0))
y (doto (make-array 1)
(aset 0 0))]
(dotimes [i (alength data)]
(let [o (aget data i)]
(aset x 0 (+ (aget x 0) (.-x o)))
(aset y 0 (+ (aget y 0) (.-y o)))))
[(aget x 0) (aget y 0)]))
(time (sumsXsAndYsWithDotimesOnArrayNativeFieldAccessAndMutableLocals data))
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您可能想查看David Nolen的Chambered项目.他有一些很好的宏来创建和更新本地变量,使上面的内容看起来不太荒谬.
无论如何,希望有所帮助.
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