解析json字符串以查找和元素(键/值)

the*_*ter 25 c# parsing json.net

我在文件timezones.json中跟随json:

  { "Atlantic/Canary": "GMT Standard Time", "Europe/Lisbon": "GMT Standard Time", 
"Antarctica/Mawson": "West Asia Standard Time", "Etc/GMT+3": "SA Eastern Standard Time", 
"Etc/GMT+2": "UTC-02", "Etc/GMT+1": "Cape Verde Standard Time", "Etc/GMT+7": "US Mountain 
Standard Time", "Etc/GMT+6": "Central America Standard Time", "Etc/GMT+5": "SA Pacific 
Standard Time", "Etc/GMT+4": "SA Western Standard Time", "Pacific/Wallis": "UTC+12", 
"Europe/Skopje": "Central European Standard Time", "America/Coral_Harbour": "SA Pacific 
Standard Time", "Asia/Dhaka": "Bangladesh Standard Time", "America/St_Lucia": "SA Western 
Standard Time", "Asia/Kashgar": "China Standard Time", "America/Phoenix": "US Mountain 
Standard Time", "Asia/Kuwait": "Arab Standard Time" }
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我想从中搜索特定的键,例如"Atlantic/Canary",因此希望它的值返回,即"GMT标准时间".

如何使用Json.Net或C#中的任何其他有效方法?

Tho*_*que 40

使用JSON解析器,如JSON.NET

string json = "{ \"Atlantic/Canary\": \"GMT Standard Time\", \"Europe/Lisbon\": \"GMT Standard Time\", \"Antarctica/Mawson\": \"West Asia Standard Time\", \"Etc/GMT+3\": \"SA Eastern Standard Time\", \"Etc/GMT+2\": \"UTC-02\", \"Etc/GMT+1\": \"Cape Verde Standard Time\", \"Etc/GMT+7\": \"US Mountain Standard Time\", \"Etc/GMT+6\": \"Central America Standard Time\", \"Etc/GMT+5\": \"SA Pacific Standard Time\", \"Etc/GMT+4\": \"SA Western Standard Time\", \"Pacific/Wallis\": \"UTC+12\", \"Europe/Skopje\": \"Central European Standard Time\", \"America/Coral_Harbour\": \"SA Pacific Standard Time\", \"Asia/Dhaka\": \"Bangladesh Standard Time\", \"America/St_Lucia\": \"SA Western Standard Time\", \"Asia/Kashgar\": \"China Standard Time\", \"America/Phoenix\": \"US Mountain Standard Time\", \"Asia/Kuwait\": \"Arab Standard Time\" }";
var data = (JObject)JsonConvert.DeserializeObject(json);
string timeZone = data["Atlantic/Canary"].Value<string>();
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  • 如果json很长,而您只需要其中一个键,那不是很有效 (2认同)

小智 24

您希望首先将其转换为对象,然后通常访问以确保将其转换为对象.

JObject obj = JObject.Parse(json);
string name = (string) obj["Name"];
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  • @ alansiqueira27然后它不是JSON。键必须是唯一的 (3认同)