symfony2 Doctrine删除一个对象数组

Question

我想从数据库中删除与Symfony2中特定user_id匹配的所有记录.

$em = $this->getDoctrine()->getManager();
$user_service = $em->getRepository('ProjectTestBundle:UserService')
->findByUser($this->getUser()->getId());

这可能会返回一些匹配的对象,所以当我运行时:

$em->remove($user_service);
$em->flush();

发生错误:

EntityManager#remove() expects parameter 1 to be an entity object, array given.

如何删除与特定条件匹配的所有记录(对象)？顺便说一下,当我在mysql中运行一个等效的sql语句时,它运行得很好.

Answer 1

你为什么不循环遍历对象数组？

$user_services = $em->getRepository('ProjectTestBundle:UserService')
->findByUser($this->getUser()->getId());

foreach ($user_services as $user_service) {
    $em->remove($user_service);
}

$em->flush();

Answer 2

您还可以使用学说查询生成器delete方法。

public function deleteAllByUser(UserInterface $user)
{
    $query = $this->createQueryBuilder('related_entity')
        ->delete()
        ->andWhere('related_entity.user = :user')
        ->setParameter('user', $user)
        ->getQuery();

    return $query->execute();
}

Answer 3

你也可以使用这样的东西：

$user_services = $em->getRepository('ProjectTestBundle:UserService')->findByUser($this->getUser()->getId());
array_walk($user_services, array($this, 'deleteEntity'), $em);
$em->flush();

然后在你的控制器中添加这个方法：

protected function deleteEntity($entity, $key, $em)
{
    $em->remove(entity);
}

或者简单地使用：

$user_services = $em->getRepository('ProjectTestBundle:UserService')->findByUser($this->getUser()->getId());
$this->deleteEntities($em, $user_services);
$em->flush();

...

protected function deleteEntities($em, $entities)
{
    foreach ($entities as $entity) {
        $em->remove($entity);
    }
}

请注意，当使用Propel和 时PropelBundle，PropelObjectCollection会实现一个delete()函数，因此您不必手动执行此循环。