选择器与android:drawable ="@ color/transparent"属性

Question

<!--  Active tab -->
<item android:state_selected="true" android:state_focused="false"
    android:state_pressed="false" android:drawable="@drawable/tab_bg_selected" />
<!--  Inactive tab -->
<item android:state_selected="false" android:state_focused="false"
    android:state_pressed="false" android:drawable="@drawable/tab_bg_unselected" />
<!--  Pressed tab -->
<item android:state_pressed="true" android:drawable="@color/transparent" />
<!--  Selected tab (using d-pad) -->
<item android:state_focused="true" android:state_selected="true"
    android:state_pressed="false" android:drawable="@color/transparent" />

有没有办法在这种选择器中得到错误我想使用这种选择器,但我得到一个错误android:drawable="@color/transparent我得到这个错误,当我运行它

我没有想法让它发挥作用

Answer 1

更换

android:drawable="@color/transparent"

同

android:drawable="@android:color/transparent"

您应该参考android命名空间

Answer 2

尝试编写代码行以获得透明度,如下所示:

 <item android:drawable="@android:color/transparent"/>