多个开关用于相同的情况

MrA*_*me8 1 java case switch-statement

我有这个代码:

switch(month){
    case 1:
        System.out.print("January");
            break;
case 2:
    System.out.print("February");
        break;
case 3:
    System.out.print("March");
        break;
case 4:
    System.out.print("April");
        break;
case 5:
    System.out.print("May");
        break;
case 6:
    System.out.print("June");
        break;
case 7:
    System.out.print("July");
        break;
case 8:
    System.out.print("August");
        break;
case 9:
    System.out.print("September");
        break;
case 10:
    System.out.print("October");
        break;
case 11:
    System.out.print("November");
        break;
case 12:
    System.out.print("December");
        break;
}
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好的,所以这个代码100%完美地工作...对于int月.我有另一个int(avgMonth)只能保持相同的值(1-12),我想只有相同的输出(月份).如何在不必复制整个交换机和案例的情况下将avgMonth添加到此代码中?我尝试使用逗号(月,avgMonth)和&&(月&& avgMonth)以及+'s(月+ avgMonth),但无济于事.

Ósc*_*pez 5

将整个代码块封装在一个方法中,并传递avgMonthmonth作为参数.像这样:

public static void monthNumToName(int month) {
    // … same as before
}
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或者,您可以使用以下方法简化代码Map:

private static final Map<Integer, String> months;
static {
    months.put(1, "January");
    months.put(2, "February");
    months.put(3, "March");
    months.put(4, "April");
    months.put(5, "May");
    months.put(6, "June");
    months.put(7, "July");
    months.put(8, "August");
    months.put(9, "September");
    months.put(10, "October");
    months.put(11, "November");
    months.put(12, "December");
}

public static void monthNumToName(int month) {
    String name = months.get(month);
    if (name == null)
        throw new IllegalArgumentException("Invalid month number: " + month);
    System.out.print(name);
}
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或者甚至更简单,只需使用数组,因为我们事先知道月份数量在1-12范围内受到限制:

private static final String[] months = {
    "January", "February", "March", "April", "May", "June",
    "July", "August", "September", "October", "November", "December"
};

public static void monthNumToName(int month) {
    if (month < 1 || month > 12)
        throw new IllegalArgumentException("Invalid month number: " + month);
    System.out.print(months[month-1]);
}
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无论如何,当你需要打印月份名称时,请执行以下操作:

monthNumToName(month);
monthNumToName(avgMonth);
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