MrA*_*me8 1 java case switch-statement
我有这个代码:
switch(month){
case 1:
System.out.print("January");
break;
case 2:
System.out.print("February");
break;
case 3:
System.out.print("March");
break;
case 4:
System.out.print("April");
break;
case 5:
System.out.print("May");
break;
case 6:
System.out.print("June");
break;
case 7:
System.out.print("July");
break;
case 8:
System.out.print("August");
break;
case 9:
System.out.print("September");
break;
case 10:
System.out.print("October");
break;
case 11:
System.out.print("November");
break;
case 12:
System.out.print("December");
break;
}
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好的,所以这个代码100%完美地工作...对于int月.我有另一个int(avgMonth)只能保持相同的值(1-12),我想只有相同的输出(月份).如何在不必复制整个交换机和案例的情况下将avgMonth添加到此代码中?我尝试使用逗号(月,avgMonth)和&&(月&& avgMonth)以及+'s(月+ avgMonth),但无济于事.
将整个代码块封装在一个方法中,并传递avgMonth和month作为参数.像这样:
public static void monthNumToName(int month) {
// … same as before
}
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或者,您可以使用以下方法简化代码Map:
private static final Map<Integer, String> months;
static {
months.put(1, "January");
months.put(2, "February");
months.put(3, "March");
months.put(4, "April");
months.put(5, "May");
months.put(6, "June");
months.put(7, "July");
months.put(8, "August");
months.put(9, "September");
months.put(10, "October");
months.put(11, "November");
months.put(12, "December");
}
public static void monthNumToName(int month) {
String name = months.get(month);
if (name == null)
throw new IllegalArgumentException("Invalid month number: " + month);
System.out.print(name);
}
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或者甚至更简单,只需使用数组,因为我们事先知道月份数量在1-12范围内受到限制:
private static final String[] months = {
"January", "February", "March", "April", "May", "June",
"July", "August", "September", "October", "November", "December"
};
public static void monthNumToName(int month) {
if (month < 1 || month > 12)
throw new IllegalArgumentException("Invalid month number: " + month);
System.out.print(months[month-1]);
}
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无论如何,当你需要打印月份名称时,请执行以下操作:
monthNumToName(month);
monthNumToName(avgMonth);
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