Che*_*Lin 7 javascript google-maps google-maps-api-3 angularjs angular-google-maps
我收到了错误:'angular-google-maps:找不到有效的中心属性'.当我看到我的locationData从php后端和exec初始化函数加载.
HTML:
<div ng-init="locationData = '<?=htmlspecialchars($data)?>'">
<google-map center="map.center" zoom="map.zoom" options="map.options"></google-map>
</div>
Run Code Online (Sandbox Code Playgroud)
角度控制器:
app.controller('MapCtrl', ['$scope', function ($scope) {
'use strict';
$scope.$watch('locationData', function() {
var location = JSON.parse($scope.locationData);
$scope.location = {
lng : location.longitude,
lat : location.latitude
initialize();
});
function initialize() {
var mapOptions = {
panControl : true,
zoomControl : true,
scaleControl : true,
mapTypeControl: true,
mapTypeId : google.maps.MapTypeId.ROADMAP
};
$scope.map = {
center: {
latitude: $scope.location.lat,
longitude: $scope.location.lng
},
zoom: 13,
options: mapOptions,
};
}
}]);
Run Code Online (Sandbox Code Playgroud)
并且,我将$ scope.map设置移动到控制器块的顶部,并将常量值设置为map
center: {
latitude: 0,
longitude: 0
},
Run Code Online (Sandbox Code Playgroud)
,地图显示正确.
角度控制器:
app.controller('MapCtrl', ['$scope', function ($scope) {
'use strict';
var mapOptions = {
panControl : true,
zoomControl : true,
scaleControl : true,
mapTypeControl: true,
mapTypeId : google.maps.MapTypeId.ROADMAP
};
$scope.map = {
center: {
latitude: 0,
longitude: 0
},
zoom: 13,
options: mapOptions,
};
}]);
Run Code Online (Sandbox Code Playgroud)
如何在加载数据后使用谷歌地图指令解析并使用后端Lat,Lng数据正确显示地图?
最后,我使用了ng-if,并在map初始化之后将map.isReady值更改false为true.
<div ng-init="locationData = '<?=htmlspecialchars($data)?>'">
<div ng-if="map.isReady">
<google-map center="map.center" zoom="map.zoom" options="map.options"></google-map>
</div>
</div>
Run Code Online (Sandbox Code Playgroud)
有用.
| 归档时间: |
|
| 查看次数: |
6791 次 |
| 最近记录: |