我有两张桌子
User
id
name
Result
id
user_id
score
created_at
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每小时一个cron作业运行并将数据放入每个用户的结果表中 - 根据一些外部变量参数为它们分配一个分数.
因此,Result表包含每个用户的许多记录.
我想在任何给定的点上回顾"前十名"用户.因此,每个用户只应返回一行,并且应该包含最近的可用分数,理想情况下,只有10行与这些分数最高的用户相关.
我目前正在获取所有结果,并使用php进行腿部工作,如果由数据库处理,我相当肯定会更快更高效.但我不知道从哪里开始.
SELECT u.id,
u.name,
r.score
FROM Result r
JOIN
(SELECT user_id, MAX(created_at) AS max_date
FROM Result
GROUP BY user_id) lr ON r.user_id=lr.user_id
JOIN User u ON u.id=r.user_id
WHERE r.created_at=lr.max_date
ORDER BY r.score DESC LIMIT 10;
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示例运行:
mysql> insert into User (name) values ('foo'), ('bar');
mysql> insert into Result (user_id, score, created_at) values (1,100,'2010-01-20'), (2,150,'2010-01-20'),(1,150,'2010-01-21'),(2,100,'2010-01-21');
mysql> SELECT u.id, u.name, r.score FROM Result r JOIN (SELECT user_id, MAX(created_at) AS max_date FROM Result GROUP BY user_id) lr ON r.user_id=lr.user_id JOIN User u ON u.id=r.user_id WHERE r.created_at=lr.max_date ORDER BY r.score DESC LIMIT 10;
+----+------+-------+
| id | name | score |
+----+------+-------+
| 1 | foo | 150 |
| 2 | bar | 100 |
+----+------+-------+
2 rows in set (0.00 sec)
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