我正在做一些报告,我想获取特定月份的所有日期,例如 2014 年 1 月,当我执行此“SQL”时:
SELECT datesInMonth WHERE month = 1 AND year = 2014;
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我想得到这个列表:
2014-01-01
2014-01-02
2014-01-03
...
2014-01-31
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如果我这样做'SQL':
SELECT datesInMonth WHERE month = 2 AND year = 2014;
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我想得到这个列表:
2014-02-01
2014-02-02
2014-02-03
...
2014-02-28
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如果我这样做'SQL':
SELECT datesInMonth WHERE month = 2 AND year = 2016;
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我想得到这个列表:
2016-02-01
2016-02-02
2016-02-03
...
2016-02-29
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这可能吗,或者我应该用我自己的表格来列出未来 100 年的日期:)
这是这个问题的mysql/java解决方案。
创建表语句:
CREATE TABLE `date_table` (
`ID` bigint(20) NOT NULL AUTO_INCREMENT,
`date` date NOT NULL,
PRIMARY KEY (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;
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Java代码:
public static void main(String[] args) throws ClassNotFoundException, SQLException {
Database db = new Database("root", "root01", "test-db", "10.10.5.11");
db.connect();
int start_year = 2013;
int end_year = 2100;
for (int year = start_year; year < end_year; year++) {
for (int month = 1; month <= 12; month++) {
int days_in_month = 0;
switch (month) {
case 1: { //January
days_in_month = 31;
break;
}
case 2: { //February
if (year % 4 == 0) {
days_in_month = 29;
} else {
days_in_month = 28;
}
break;
}
case 3: { //March
days_in_month = 31;
break;
}
case 4: { //April
days_in_month = 30;
break;
}
case 5: { //May
days_in_month = 31;
break;
}
case 6: { //June
days_in_month = 30;
break;
}
case 7: { //July
days_in_month = 31;
break;
}
case 8: { //August
days_in_month = 31;
break;
}
case 9: { //September
days_in_month = 30;
break;
}
case 10: { //October
days_in_month = 31;
break;
}
case 11: { //November
days_in_month = 30;
break;
}
case 12: { //December
days_in_month = 31;
break;
}
}
for (int day = 1; day <= days_in_month; day++) {
db.executeInsert("INSERT INTO date_table (date) VALUES ('" + year + "-" + month + "-" + day + "');");
}
}
System.out.println("YEAR: " + year + " FINISHED");
}
}
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我使用此 sql 获取日期列表:
SELECT * FROM date_table WHERE YEAR(date) = 2014 AND MONTH(date) = 2;
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希望有人使用它:)