用于URL的百分比转义'&'的NSString方法

Question

哪种NSString编码方法将百分比(&)字符正确地转义为%26？

stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding

获取空格(%20)和其他坏人但忽略了&符号!？!

Answer 1

Ampersands不会被该方法处理,因为它们是URL中的合法字符.在此调用之前,您应该可以预先处理特别有问题的碎片.

Answer 2

以下是从Bagonca博客中对您的NSStrings进行url编码的问题的一个很好的解决方案:

+ (NSString *)urlEncodeValue:(NSString *)str
{
   NSString *result = (NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (CFStringRef)str, NULL, CFSTR(":/?#[]@!$&’()*+,;="), kCFStringEncodingUTF8);
   return [result autorelease];
}

添加CFBridgingRelease(ARC兼容性.

+ (NSString *)urlEncodeValue:(NSString *)str
{
    NSString *result = (NSString *)CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (CFStringRef)str, NULL, CFSTR(":/?#[]@!$&’()*+,;="), kCFStringEncodingUTF8));
    return result;
}

Answer 3

接受的答案不太正确我不认为,你需要在调用addPercentEscapesAndReplaceAmpersand 后处理字符串

+ (NSString *) addPercentEscapesAndReplaceAmpersand: (NSString *) stringToEncode
{
    NSString *encodedString = [stringToEncode stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding]; 
    return [encodedString stringByReplacingOccurrencesOfString: @"&" withString: @"%26"];
}