keg*_*ewe 6 html python parsing beautifulsoup
我有以下HTML代码:
<td class="image">
<a href="/target/tt0111161/" title="Target Text 1">
<img alt="target img" height="74" src="img src url" title="image title" width="54"/>
</a>
</td>
<td class="title">
<span class="wlb_wrapper" data-caller-name="search" data-size="small" data-tconst="tt0111161">
</span>
<a href="/target/tt0111161/">
Other Text
</a>
<span class="year_type">
(2013)
</span>
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我正在尝试使用漂亮的汤将某些元素解析为制表符分隔的文件。我得到了很大的帮助,并且有:
for td in soup.select('td.title'):
span = td.select('span.wlb_wrapper')
if span:
print span[0].get('data-tconst') # To get `tt0082971`
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现在,我想获取“目标文本1”。
我已经尝试过类似上述内容的操作,例如:
for td in soup.select('td.image'): #trying to select the <td class="image"> tag
img = td.select('a.title') #from inside td I now try to look inside the a tag that also has the word title
if img:
print img[2].get('title') #if it finds anything, then I want to return the text in class 'title'
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如果您试图根据类获得不同的 td(即 td class="image" 和 td class="title",您可以使用 Beautiful Soup 作为字典来获取不同的类。
这将在表中找到所有 td class="image"。
from bs4 import BeautifulSoup
page = """
<table>
<tr>
<td class="image">
<a href="/target/tt0111161/" title="Target Text 1">
<img alt="target img" height="74" src="img src url" title="image title" width="54"/>
</a>
</td>
<td class="title">
<span class="wlb_wrapper" data-caller-name="search" data-size="small" data-tconst="tt0111161">
</span>
<a href="/target/tt0111161/">
Other Text
</a>
<span class="year_type">
(2013)
</span>
</td>
</tr>
</table>
"""
soup = BeautifulSoup(page)
tbl = soup.find('table')
rows = tbl.findAll('tr')
for row in rows:
cols = row.find_all('td')
for col in cols:
if col.has_attr('class') and col['class'][0] == 'image':
hrefs = col.find_all('a')
for href in hrefs:
print href.get('title')
elif col.has_attr('class') and col['class'][0] == 'title':
spans = col.find_all('span')
for span in spans:
if span.has_attr('class') and span['class'][0] == 'wlb_wrapper':
print span.get('data-tconst')
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