将两个哈希与一个公共密钥组合在一起

Question

我一直在尝试在Ruby中组合两个哈希.例如:

h1 = { "a" => 10, "b" => 20, "c"=>34, "d"=>3}
h2 = { "a" => 11, "b" => 21, "d"=>15}

我想要的输出是:

h{"a"=> 10, 11, "b"=>20,21, "c"=> 34, "d"=>3,15}

每个哈希都有相同的密钥,除了第二个哈希可能缺少一些.我想这两个值然后由相同的键表示.

这是我不成功的代码:

h1 = { "a" => 10, "b" => 20, "c"=>34, "d"=>3}   
h2 = {  "a" => 11, "b" => 21, "d"=>15}  
h3= h1.update(h2){|key1, key2, val1, val2 |key1,h2_val=h2}

它给:

{"a"=>{"a"=>11, "b"=>21, "d"=>15}, "b"=>{"a"=>11, "b"=>21, "d"=>15}, "c"=>34, "d"=>{"a"=>11, "b"=>21, "d"=>15}}

我刚接触Ruby,所以我想我在这里缺少一些非常基本的东西.我将不胜感激任何帮助.

Answer 1

关于什么:

h1 = { "a" => 10, "b" => 20, "c"=>34, "d"=>3} 
h2 = { "a" => 11, "b" => 21, "d"=>15}

p h1.merge(h2){|key, old, new| Array(old).push(new) } #=> {"a"=>[10, 11], "b"=>[20, 21], "c"=>34, "d"=>[3, 15]}

这就是我如何编写它来组合2个以上的哈希:

h1 = { "a" => 10, "b" => 20, "c"=>34, "d"=>3} 
h2 = { "a" => 11, "b" => 21, "d"=>15}
h3 = { "a" => 11, "b" => 21, "c"=> 1, "d"=>15}

merge_to_array = -> x,y { x.merge(y){|key, old, new| Array(old).push(new)} }

p [h1,h2,h3].reduce &merge_to_array #=> {"a"=>[10, 11, 11], "b"=>[20, 21, 21], "c"=>[34, 1], "d"=>[3, 15, 15]}