scala's尝试优雅的错误行为

Question

在scala中有更优雅的方法吗？

def doTheDangerousThing(): Try[Result] = {
  val result = Try(dangerousOp)

  if (result.isFailure) {
     println("error")
  }

  result
}

Answer 1

我认为你的if语句完全有效.这是另一种选择:

def doTheDangerousThing(): Try[Result] = Try(dangerousOp) recoverWith {
    case exception => println("error"); Failure(exception)
}

Answer 2

好吧，我想你可以这样做：

def doTheDangerousThing(): Option[Result] = 
  Try(dangerousOp) match {
    case Success(result) => Some(result)
    case Failure(e) => None //might want to log the error as well
  }