use*_*594 0 shell search awk grep sed
我有这样的文件
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
Do the best part now
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
Do the best part now
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
Do the best part now
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
Do the best part now
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
Do the best part now
我想在"寻找一个小鸡"的第三场比赛后添加一条线等待
所以上面应该读.
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
Do the best part now
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
Do the best part now
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
**wait**
Do the best part now
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
Do the best part now
Go to Vegas
Play the blackjack
Earn a lucky wad
Find a hot chick
Do the best part now
在每N个字符串的匹配后插入另一行(在这种情况下它的"等待")
如何才能做到最好我可以在每个模式匹配后添加一个新行,但我想在每个第N个模式匹配后添加一个特定的行这个
sed '/"Find a hot chick"/ a\
wait ' <filename>
像这样:
awk '1;/Find a hot chick/{if(i++==3){print "New line";i=0}}' yourfile
"1"只是为每行提供awk默认的东西,即打印.