斯卡拉从字符串unpickling

Question

我尝试了以下单元测试.

第一次测试testUnpickleJsonPickleFormat效果很好.它腌制一个字符串并取出泡菜.

testUnpickleString{1,2}测试以反序列化String.但它们根本不起作用.我不知道哪里有什么想念我.

import org.junit.Test

import scala.pickling._
import scala.pickling.json._

class PicklerTest {

  @Test
  def testUnpickleJsonPickleFormat {
    val src = "elem 1"
    val pckl = src.pickle
    val res = pckl.unpickle[String]
    println(src)
    println(pckl.toString +"\n")
    println(res)
  }

  @Test
  def testUnpickleString1 {
    val json = """JSONPickle({
                 |      "tpe": "java.lang.String",
                 |      "value": "elem 1"
                 |    })""".stripMargin.trim
    val pckl = JSONPickle(json.toString)
    val res = pckl.unpickle[String]

  }

  @Test
  def testUnpickleString2 {
    val src = "elem 1"
    val pckl = src.pickle
    val pckl2 = JSONPickle(pckl.toString)
    val res = pckl2.unpickle[String]
    println(src)
    println(pckl.toString +"\n")
    println(res)
  }
}

我不知道如何在Scala Pickle框架中使用unpickle.

Answer 1

你应该用

{
  "tpe": "java.lang.String",
  "value": "elem 1"
}

没有JSONPickle(...):

val json = """{
  "tpe": "java.lang.String",
  "value": "elem 1"
}"""

JSONPickle(json).unpickle[String]
// String = elem 1

JSONPickle({...})不是有效的JSON.

您还应该使用pckl.value的,而不是pckl.toString来获得JSON无JSONPickle(...):

val src = "elem 1"
val pckl = src.pickle
val pckl2 = JSONPickle(pckl.value)
pckl2.unpickle[String]
// String = elem 1

你也可以像这样使用模式匹配:

val src = "elem 2"
val pckl = src.pickle
val pckl2 = pckl match {
  case JSONPickle(value) => JSONPickle(value)
} 
pckl2.unpickle[String]
// String = elem 2