Siv*_*iva 0 c linux time gettime gettimeofday
我需要计算运行某个函数所需的时间并运行以下代码,以纳秒为单位记录并输出一段代码的执行时间
并且也有任何区别
struct timeval timer_spent & timeval timer_spent
/* Put this line at the top of the file: */
#include <sys/time.h>
/* Put this right before the code you want to time: */
struct timeval timer_start, timer_end;
gettimeofday(&timer_start, NULL);
/* Put this right after the code you want to time: */
gettimeofday(&timer_end, NULL);
double timer_spent = timer_end.tv_sec - timer_start.tv_sec + (timer_end.tv_usec - timer_start.tv_usec);
printf("Time spent: %.6f\n", timer_spent)/1000000.0;
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但我需要精确的时间,以纳秒为单位.我对timeval结构没有完全的了解.
亲切地帮助我们.. !!
但我需要精确的时间,以纳秒为单位.
然后用
int clock_gettime(clockid_t clk_id, struct timespec *tp);
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它以秒和纳秒返回时间
struct timespec {
time_t tv_sec; /* seconds */
long tv_nsec; /* nanoseconds */
};
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有用的链接: