Python：获取Json文件中一个属性的项目（按值）

Question

我想提取 json 文件的所有值。例如我有这个对象，我想获取所有“文本”值。我怎样才能做到这一点 ？

  list= [
    {
    "text": "contact solution - COUPON",
    "listId": "1",
    "id": "4",
    "leaf": "true" 
    },
    {
    "text": "Falafel (bulk)",
    "listId": "1",
    "id": "161",
    "leaf": "true" 
    },
    {
    "text": "brita filters",
    "listId": "1",
    "id": "166",
    "leaf": "false" 
    }

输出：

listText = ["contact solution - COUPON","Falafel (bulk)","brita filters"]

更新：

我从 CSV 文件获取这些数据。

text,listId,id,leaf, jsonfile
"1","is","an","example","{ "text": "contact solution - COUPON", "listId": "1", "id": "4","leaf": "true"}"
"2","is","an","example"," { "text": "Falafel (bulk)","listId": "1", "id": "161", "leaf": "true"  }"
"3","is","an","example"," { "text": "Falafel (bulk)","listId": "1","id": "161","leaf": "true" }"
"4","is","an","example"," { "text": "brita filters","listId": "1","id": "166","leaf":"false" }"
"5","is","an","example"
"6","is","an","example"
"7","is","an","example"

使用 Pandas，我将列的项目转换为列表。

with open("data/output.csv", "rb") as csvfile:
    df = pd.read_csv(csvfile)
    addData = df.Address
        listfiels= df.jsonfile

现在，我想获取 Json 文件中的“文本”列表，以这种方式将其存储到其他 json 文件中。我需要 YYY 列表，每次都选择 XXX。

output = [  {
            "type": "User",
            "name": {
                "status": "Single",
                "adress":coordinates
                "details": XXXX }
            }
          for da,coordinates in zip(textData, addData,YYYY )]

这有意义吗？我用 JS 做了这个，没有任何问题。

 var globalData = data.map(function(d) {
            return JSON.parse(d.Jsonfile);
        });

我可以毫无问题地访问文本字段。

UPDATE2： j = json.loads(listfiels[0]) print(j['text'])

我可以成功打印：“联系解决方案 - COUPON”

Answer 1

使用列表理解：

>>> lst = [
...     {
...         "text": "contact solution - COUPON",
...         "listId": "1",
...         "id": "4",
...         "leaf": "true" 
...     },
...     {
...         "text": "Falafel (bulk)",
...         "listId": "1",
...         "id": "161",
...         "leaf": "true" 
...     },
...     {
...         "text": "brita filters",
...         "listId": "1",
...         "id": "166",
...         "leaf": "false" 
...     }
... ]
>>> [d['text'] for d in lst]
['contact solution - COUPON', 'Falafel (bulk)', 'brita filters']

map与以下一起使用operator.itemgetter：

>>> import operator
>>> list(map(operator.itemgetter('text'), lst)) # Omit `list` in Python 2.x
['contact solution - COUPON', 'Falafel (bulk)', 'brita filters']