HTML代码
<!DOCTYPE html>
<html>
<head>
<style>
#right
{
margin-top:109px;
margin-right:225px;
}
#button
{
margin-right:;
margin-top:22px;
}
</style>
</head>
<body>
<div id="total" style="width:1350px">
<div id="top" style="width:1350px;height:69px;background-image:url('top.png');float:;"></div>
<div id="body" style="width:1350px;height:570px;background-image:url('body.jpg');float:;">
<div id="right" style="background-color:;height:283px;width:320px;float:right;">
<form action="new.php" method="post" >
<input type="text" name="username" value="" size="37" placeholder="username"style="height:20px"><br><br>
<pre><input type="password" name="password" value="" size="37" placeholder="password"style="height:20px">
<div id="button"><input type="image" name="" value="submit" src="button.png" /> <input type="checkbox" value="check"><br></pre>
</div>
</form>
</div>
</div>
<div id="footer" style="width:1350px;height:33px;background-image:url('footer.png');clear:both;"></div>
</div>
</body>
</html>
Run Code Online (Sandbox Code Playgroud)
我的PHP代码
<?php
$con=mysqli_connect("localhost","prabha","prabha","prabha");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="INSERT INTO table (username, password)
VALUES
('$_POST[username]','$_POST[password]')";
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
echo "1 record added";
mysqli_close($con);
?>
Run Code Online (Sandbox Code Playgroud)
当我输入用户名后点击提交按钮:prabha密码:passwordofprabha
它显示以下错误.请修复我的代码.
错误:SQL语法中有错误; 检查与MySQL服务器版本对应的手册,以便在第1行的'table(用户名,密码)VALUES('prabha','passwordofprabha')附近使用正确的语法
use*_*933 18
对MYSQL保留字使用`反引号...
表名"table"是MYSQL的保留字...
所以你的查询应该如下......
$sql="INSERT INTO `table` (`username`, `password`)
VALUES
('$_POST[username]','$_POST[password]')";
Run Code Online (Sandbox Code Playgroud)