sma*_*use 16 java final inner-classes
ratingS = new JSlider(1, 5, 3);
ratingS.setMajorTickSpacing(1);
ratingS.setPaintLabels(true);
int vote;
class SliderMoved implements ChangeListener {
public void stateChanged(ChangeEvent e) {
vote = ratingS.getValue();
}
}
ratingS.addChangeListener(new SliderMoved());
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如果我写上面的代码Eclipse告诉我这个:
不能在不同方法中定义的内部类中引用非最终变量vote
但如果我在int vote之前添加final,它会给我这个错误:
无法分配最终的局部变量投票,因为它是在封闭类型中定义的
那么,如何解决?
Mar*_*nik 28
好吧,标准技巧是使用长度为1的int数组.使var final并写入var[0].确保不创建数据竞争非常重要.以您的代码为例:
final int[] vote = {0};
class SliderMoved implements ChangeListener {
public void stateChanged(ChangeEvent e) {
vote[0] = ratingS.getValue();
}
}
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由于所有这些都将在EDT上发生,包括回调调用,你应该是安全的.您还应该考虑使用匿名类:
ratingS.addChangeListener(new ChangeListener() {
public void stateChanged(ChangeEvent e) { vote[0] = ratingS.getValue(); }
});
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移动vote到SliderMoved:
class SliderMoved implements ChangeListener {
private int vote;
public void stateChanged(ChangeEvent e) {
this.vote = ratingS.getValue();
// do something with the vote, you can even access
// methods and fields of the outer class
}
public int getVote() {
return this.vote;
}
}
SliderMoved sm = new SliderMoved();
ratingS.addChangeListener(sm);
// if you need access to the actual rating...
int value = rattingS.getValue();
// ...or
int value2 = sm.getVote();
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编辑
或者,将模型类传递给更改侦听器
public class Person {
private String name;
private int vote;
public int getVote() {
return this.vote;
}
public void setVote(int vote) {
this.vote = vote;
}
// omitting other setter and getter
}
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Person 用法如下:
class SliderMoved implements ChangeListener {
private Person person;
public SliderMoved(Person person) {
this.person = person;
}
public void stateChanged(ChangeEvent e) {
this.person.setVote(ratingS.getValue());
}
public Person getPerson() {
return this.person;
}
}
Person person = new Person();
ratingS.addChangeListener(new SliderMoved(person));
// access the vote
int vote = person.getVote();
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