ak8*_*k85 4 mysql sql select inner-join subquery
我有以下查询,该查询来自这篇文章计数 mysql 中的一行中的项目数,它计算学生连续出席/缺席课堂的次数。
SELECT
classlist.studentid,
student.name,
classStatus.name status,
COUNT(*) presentcnt
FROM
classlist
INNER JOIN student ON classlist.studentid=student.id
INNER JOIN classstatus ON classlist.presentid=classstatus.id
INNER JOIN (
SELECT
studentid,
max(CASE WHEN presentid=0 THEN id END) max_0,
max(CASE WHEN presentid=1 THEN id END) max_1
FROM classlist
GROUP BY studentid
) s
ON coalesce(classlist.id>least(max_0,max_1) AND classlist.id<=greatest(max_0,max_1),1) AND s.studentid=classlist.studentid
GROUP BY classlist.studentid
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这按预期工作,
STUDENTID NAME STATUS PRESENTCNT
111 John Present 1
222 Kate Absent 2
333 Matt Present 5
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我想扩展查询,以便有一列显示学生是否参加了课程。
如果我运行独立查询,我会得到我想要的结果
SELECT
classlist.studentid,
student.name,
participatedStatus.name status,
COUNT(*) participatedcnt
FROM
classlist
INNER JOIN student ON classlist.studentid=student.id
INNER JOIN participatedStatus ON classlist.participatedid=participatedStatus.id
INNER JOIN (
SELECT
studentid,
max(CASE WHEN participatedid=0 THEN id END) max_0,
max(CASE WHEN participatedid=1 THEN id END) max_1
FROM classlist
group by studentid
) s
ON coalesce(classlist.id>least(max_0,max_1)
AND classlist.id<=greatest(max_0,max_1),1)
AND s.studentid=classlist.studentid
group by classlist.studentid
STUDENTID NAME STATUS PARTICIPATEDCNT
111 John Yes 1
222 Kate No 2
333 Matt Yes 2
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不过我想将它们合并到一个查询中,这样我就得到了
STUDENTID NAME STATUS PRESENTCNT STATUS2 PARTICIPATEDCNT
111 John Present 1 Yes 1
222 Kate Absent 2 No 2
333 Matt Present 5 Yes 2
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当我选择 count * 时,我对如何实现这一点感到困惑,我怎样才能实现这一点?
我正在使用的数据示例位于此小提琴和下面
CREATE TABLE classlist
(`id` int, `studentid` int, `subjectid` int, `presentid` int, `participatedid` int);
CREATE TABLE student
(`id` int, `name` varchar(4));
CREATE TABLE subject
(`id` int, `name` varchar(4));
CREATE TABLE classStatus
(`id` int, `name` varchar(8));
CREATE TABLE participatedStatus
(`id` int, `name` varchar(8));
INSERT INTO classlist (`id`, `studentid`, `subjectid`, `presentid`, `participatedid`)
VALUES (1, 111, 1, 1, 0), (2, 222, 3, 0, 0), (3, 333, 2, 1, 0), (4, 111, 4, 0, 0), (5, 111, 1, 1, 0), (6, 222, 3, 0, 0), (7, 333, 2, 1, 1), (8, 111, 4, 0, 0), (9, 111, 4, 0, 0), (10, 111, 4, 0, 0), (11, 111, 1, 1, 1), (12, 333, 3, 1, 0), (13, 333, 2, 1, 1), (14, 333, 3, 1, 1);
INSERT INTO student (`id`, `name`)
VALUES (111, 'John'),(222, 'Kate'),(333, 'Matt');
INSERT INTO subject (`id`, `name`)
VALUES (1, 'MATH'),(2, 'ENG'),(3, 'SCI'),(4, 'GEO');
INSERT INTO classStatus (`id`, `name`)
VALUES (0, 'Absent'), (1, 'Present');
INSERT INTO participatedStatus (`id`, `name`)
VALUES (0, 'No'),(1, 'Yes');
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SELECT
studid,
studname,
status,
presentcnt,
status1,
participatedcnt FROM
(SELECT
classlist.studentid studid,
student.name studname,
classStatus.name status,
COUNT(*) presentcnt
FROM
classlist
INNER JOIN student ON classlist.studentid=student.id
INNER JOIN classstatus ON classlist.presentid=classstatus.id
INNER JOIN (
SELECT
studentid,
max(CASE WHEN presentid=0 THEN id END) max_0,
max(CASE WHEN presentid=1 THEN id END) max_1
FROM classlist
GROUP BY studentid
) s
ON coalesce(classlist.id>least(max_0,max_1) AND classlist.id<=greatest(max_0,max_1),1) AND s.studentid=classlist.studentid
GROUP BY classlist.studentid)x
JOIN
(SELECT
classlist.studentid,
student.name,
participatedStatus.name status1,
COUNT(*) participatedcnt
FROM
classlist
INNER JOIN student ON classlist.studentid=student.id
INNER JOIN participatedStatus ON classlist.participatedid=participatedStatus.id
INNER JOIN (
SELECT
studentid,
max(CASE WHEN participatedid=0 THEN id END) max_0,
max(CASE WHEN participatedid=1 THEN id END) max_1
FROM classlist
group by studentid
) s
ON coalesce(classlist.id>least(max_0,max_1)
AND classlist.id<=greatest(max_0,max_1),1)
AND s.studentid=classlist.studentid
group by classlist.studentid)y
ON x.studid=y.studentid
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