curl命令等效于ruby

Question

我有一个运行良好的curl命令,但我需要在ruby脚本中自动执行此操作,

卷曲cmd:

curl -u usrname:pwd -X POST --data "del=false&val=100" http://localhost:1111/sample/path

我写了以下代码:

uri = URI::HTTPS.build(:host => "localhost", :port => 1111)
uri.path = URI.escape("/sample/path")
client = Net::HTTP.new("localhost", "1111")
req = Net::HTTP::Post.new(uri.request_uri, {"User-Agent" => "UA"})
req.set_form_data({"del" => "false", "val" => "100"})
req.basic_auth("usrname", "pwd")
res = client.request(req)

上面的代码工作正常,我有一个编码的URL我传递给URI.escape,这让我发布了关于错误响应的问题.Foud问题并修复它:)

Answer 1

最好的和简单的解决方案!

1. 复制您的CURL代码.

2. 转到此页面.

3. 粘贴您的CURL代码.

4. 要开心.

我在这个页面上测试了这个解决方

Answer 2

你可以直接从ruby执行curl命令

usrname = "username"
pwd = "pwd"
val = 100
del= false
http_path = "http://localhost:1111/sample/path"
puts `curl -u #{usrname}:#{pwd} -X POST --data "del=#{del}&val=#{va}" #{http_path}`

并且后面的刻度将执行系统卷曲

Answer 3

您可以使用路边

c = Curl::Easy.new

c.http_auth_types = :basic
c.username = 'usrname'
c.password = 'pwd'

c.http_post("http://localhost:1111/sample/path", "del=false&val=100")