HTTPS连接Python

chr*_*ley 42 python ssl https pyopenssl httplib

我正在尝试验证该目标是否公开了https Web服务.我有通过HTTP连接的代码,但我不知道如何通过HTTPS连接.我读过你使用SSL,但我也读过它不支持证书错误.我得到的代码来自python文档:

import httplib
conn = httplib.HTTPConnection("www.python.org")
conn.request("GET", "/index.html")
r1 = conn.getresponse()
print r1.status, r1.reason
Run Code Online (Sandbox Code Playgroud)

有谁知道如何连接到HTTPS?

我已经尝试了HTTPSConenction,但它响应了一个错误代码,声称httplib没有属性HTTPSConnection.我也没有socket.ssl可用.

我已经安装了Python 2.6.4,我认为它没有编译SSL支持.有没有办法将这个支持集成到较新的python中,而无需再次安装它.

我已经安装了OpenSSL和pyOpenSsl,我从其中一个答案中尝试了以下代码:

import urllib2
from OpenSSL import SSL
try: 
    response = urllib2.urlopen('https://example.com')  
    print 'response headers: "%s"' % response.info() 
except IOError, e: 
    if hasattr(e, 'code'): # HTTPError 
        print 'http error code: ', e.code 
    elif hasattr(e, 'reason'): # URLError 
        print "can't connect, reason: ", e.reason 
    else: 
        raise
Run Code Online (Sandbox Code Playgroud)

我有一个错误:

    Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
  File "/home/build/workspace/downloads/Python-2.6.4/Lib/urllib.py", line 87, in urlopen
    return opener.open(url)
  File "/home/build/workspace/downloads/Python-2.6.4/Lib/urllib.py", line 203, in open
    return self.open_unknown(fullurl, data)
  File "/home/build/workspace/downloads/Python-2.6.4/Lib/urllib.py", line 215, in open_unknown
    raise IOError, ('url error', 'unknown url type', type)
IOError: [Errno url error] unknown url type: 'https'
Run Code Online (Sandbox Code Playgroud)

有谁知道如何使这个工作?

-- UPDATE
Run Code Online (Sandbox Code Playgroud)

我发现问题是什么,我使用的Python版本没有SSL支持.我现在找到了这个解决方案:http://www.webtop.com.au/compiling-python-with-ssl-support.

代码现在可以在此解决方案之后工作,这非常好.当我导入ssl和HTTPSConnection时,我知道不会收到错误.

谢谢大家的帮助.

mik*_*iku 64

Python 2.x:docs.python.org/2/library/httplib.html:

注意:只有在使用SSL支持编译套接字模块时,HTTPS支持才可用.

Python 3.x:docs.python.org/3/library/http.client.html:

注意HTTPS支持仅在Python使用SSL支持编译时才可用(通过ssl模块).

#!/usr/bin/env python

import httplib
c = httplib.HTTPSConnection("ccc.de")
c.request("GET", "/")
response = c.getresponse()
print response.status, response.reason
data = response.read()
print data
# => 
# 200 OK
# <!DOCTYPE html ....
Run Code Online (Sandbox Code Playgroud)

要验证是否启用了SSL,请尝试:

>>> import socket
>>> socket.ssl
<function ssl at 0x4038b0>
Run Code Online (Sandbox Code Playgroud)

  • 请注意,这不会验证远程证书,因此您不会以这种方式获得安全性(因为您实际上并不知道您正在与哪个服务器通信). (9认同)

jfs*_*jfs 13

要检查Python 2.6+中的ssl支持:

try:
    import ssl
except ImportError:
    print "error: no ssl support"
Run Code Online (Sandbox Code Playgroud)

要通过https进行连接:

import urllib2

try:
    response = urllib2.urlopen('https://example.com') 
    print 'response headers: "%s"' % response.info()
except IOError, e:
    if hasattr(e, 'code'): # HTTPError
        print 'http error code: ', e.code
    elif hasattr(e, 'reason'): # URLError
        print "can't connect, reason: ", e.reason
    else:
        raise
Run Code Online (Sandbox Code Playgroud)


小智 10

import requests
r = requests.get("https://stackoverflow.com") 
data = r.content  # Content of response

print r.status_code  # Status code of response
print data
Run Code Online (Sandbox Code Playgroud)


gog*_*sca 6

如果使用httplib.HTTPSConnection:

请看一下:版本2.7.9中的更改:

此类现在默认执行所有必需的证书和主机名检查.要恢复到先前未验证的行为,可以将ssl._create_unverified_context()传递给context参数.您可以使用:

if hasattr(ssl, '_create_unverified_context'):
  ssl._create_default_https_context = ssl._create_unverified_context
Run Code Online (Sandbox Code Playgroud)


Pio*_*pla 5

为什么你没有尝试过httplib.HTTPSConnection?它不进行SSL验证,但不需要通过https进行连接.您的代码可以正常使用https连接:

>>> import httplib
>>> conn = httplib.HTTPSConnection("mail.google.com")
>>> conn.request("GET", "/")
>>> r1 = conn.getresponse()
>>> print r1.status, r1.reason
200 OK
Run Code Online (Sandbox Code Playgroud)