Ash*_*win 8 c++ overriding virtual-functions name-hiding
我低于警告.我的部分代码是:
class Base {
public:
virtual void process(int x) {;};
virtual void process(int a,float b) {;};
protected:
int pd;
float pb;
};
class derived: public Base{
public:
void process(int a,float b);
}
void derived::process(int a,float b){
pd=a;
pb=b;
....
}
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我收到以下警告:
Warning: overloaded virtual function "Base::process" is only partially overridden in class "derived"
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我以任何方式将进程作为虚函数,所以我期待这个警告不应该来......这背后的原因是什么?
警告的原因
Warning: overloaded virtual function "Base::process" is only partially overridden in class "derived"
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是你没有覆盖所有签名,你已经完成了
virtual void process(int a,float b) {;}
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但不是
virtual void process(int x) {;}
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另外,当你不覆盖并且不使用using Base::process将函数带到范围时,静态调用derived::process(int)甚至都不会编译.这是因为Derived process(int)在这种情况下没有.所以
Derived *pd = new Derived();
pd->process(0);
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和
Derived d;
d.process(0);
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不会编译.
添加using声明将解决此问题,通过指向Derived*的指针和选择运算符d.process(int)进行静态调用以进行编译和虚拟调度(通过基指针或引用调用派生)进行编译,无需警告.
class Base {
public:
virtual void process(int x) {qDebug() << "Base::p1 ";};
virtual void process(int a,float b) {qDebug() << "Base::p2 ";}
protected:
int pd;
float pb;
};
class derived: public Base{
public:
using Base::process;
/* now you can override 0 functions, 1 of them, or both
* base version will be called for all process(s)
* you haven't overloaded
*/
void process(int x) {qDebug() << "Der::p1 ";}
void process(int a,float b) {qDebug() << "Der::p2 ";}
};
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现在:
int main(int argc, char *argv[])
{
derived d;
Base& bref = d;
bref.process(1); // Der::p1
bref.process(1,2); // Der::p2
return 0;
}
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您仅覆盖了 的两个重载之一process。您错过了仅使用int.
class Base {
public:
virtual void process(int x) {;}; // You do *not* override this in derived
virtual void process(int a,float b) {;}; // You do override this
// ...
};
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根据您的需要,您可以:
只需覆盖;int中的重载即可。derived或者
使int重载成为非虚拟的并让它调用虚拟int, float重载。
两个旁注: (a) 尽管大多数编译器都接受它,但;函数体后面的 a 在语法上是错误的。(b) 受保护的成员变量通常与公共变量一样不受欢迎;您应该使用受保护的 getter/setter 并将变量设为私有。