在我的项目中在客户端工作的团队要求我编写一个示例测试页面,并为他们提供一个可以点击并返回200的工作URL.他们要求我也提供样本请求正文.这是我要给他们的请求主体.
{
"MyApp": {
"mAppHeader": {
"appId": "",
"personId": "",
"serviceName": "",
"clientIP": "",
"requestTimeStamp": "",
"encoding": "",
"inputDataFormat": "",
"outputDataFormat": "",
"environment": ""
},
"requestPayload": {
"header": {
"element": ""
},
"body": {
"request": {
"MyTestApp": {
"data": {
"AuthenticationRequestData": {
"appId": "",
"appPwd": ""
}
}
}
}
}
}
}
}
要开发示例页面,我不知道从哪里开始.请放弃你的downvotes(如果问题似乎无关紧要),因为我没有使用JSP Servlets的经验.
这就是我现在所拥有的.它是一个简单的登录页面 -
<%@ page language="java"
contentType="text/html; charset=windows-1256"
pageEncoding="windows-1256"
%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=windows-1256">
<title>Login Page</title>
</head>
<body>
<form action="TestClient">
AppId
<input type="text" name="appID"/><br>
AppPassword
<input type="text" name="appPwd"/>
<input type="submit" value="submit">
</form>
</body>
</html>
这是我的servlet类 -
package com.test;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class TestClient extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public TestClient() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/json");
App app = new App();
app.setAppID(request.getParameter("appID"));
app.setAppPassword(request.getParameter("appPwd"));
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
}
}
我的应用程序是一个简单的Java类,它有appID,appPassword有getter和setter,所以我不打算在这里发布.
我的问题是 - 我这样做是对还是100%错了？请给我你的建议.
在 doGet 方法中使用 Gson jarLibrary 生成 JSON 响应
像下面这样
Gson gson = new Gson();
HashMap map = new HashMap();
map.put("MyApp",object);
String jsonString = gson.toJson(map);
PrintWriter writer = response.getWriter();
writer.print(jsonString);