检查日期是否晚于当前日期

Question

如何检查日期是否晚于当前日期？

if(date("d") < "18" && date("m") < "01") { 
    echo 'To late!';
}

对我不起作用.

Answer 1

你可以这样做:

if( '20140505' > date("Ymd") ) {
    // today's date is before 20140505 (May 5, 2014)
}

Answer 2

$time1  = strtotime(date("d/m/Y", "18/01/2014"));
  if(time() > $time1)
   {
     echo "too late!";
   }