use*_*224 6 f# type-parameter type-providers f#-data
我正在使用FSharp.Data.JsonProvider
Twitter推文.
使用此示例代码 https://github.com/tpetricek/Documents/tree/master/Samples/Twitter.API
我想扩展推文中的网址
let expandUrl (txt:string) (url:Search.DomainTypes<...>.DomainTypes.Url) =
txt.Replace( url.Url, url.ExpandedUrl )
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这会导致错误:
Lookup on object of indeterminate type based on information prior to this program point.
A type annotation may be needed prior to this program point to constrain the type of the object.
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我的问题是如何TypeProvider
在上面的expandUrl函数中定义url 的类型?
类型感染告诉我这个
val urls : FSharp.Data.JsonProvider<...>.DomainTypes.Url []
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但是在类型声明中不接受这一点.我假设"<...>"不是F#synatx.
如何使用TypeProvider类型进行类型注释,例如 FSharp.Data.JsonProvider<...>.DomainTypes.Url ?
以下是完整的代码段:
open TwitterAPI // github.com/tpetricek/Documents/tree/master/Samples/Twitter.API
let twitter = TwitterAPI.TwitterContext( _consumerKey, _consumerSecret, _accessToken, _accessTokenSecret )
let query = "water"
let ts = Twitter.Search.Tweets(twitter, Utils.urlEncode query, count=100)
let ret =
[ for x in ts.Statuses do
// val urls : FSharp.Data.JsonProvider<...>.DomainTypes.Url []
let urls = x.Entities.Urls
// fully declarated to help the type inference at expandUrl
let replace (txt:string) (oldValue:string) (newValue:string) =
txt.Replace( oldValue, newValue)
// Error:
// Lookup on object of indeterminate type based on information prior to this program point.
// A type annotation may be needed prior to this program point to constrain the type of the object.
// This may allow the lookup to be resolved.
let expandUrl (txt:string) (url:FSharp.Data.JsonProvider<_>.DomainTypes.Url) =
replace txt url.Url url.ExpandedUrl
let textWithExpandedUrls = Array.fold expandUrl x.Text urls
yield textWithExpandedUrls
]
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当您调用Twitter.Search.Tweets
(https://github.com/tpetricek/Documents/blob/master/Samples/Twitter.API/Twitter.fs#L284)时,其返回类型是 的域类型之一TwitterTypes.SearchTweets
,这是一种类型JsonProvider<"references\\search_tweets.json">
( https://github.com/tpetricek/Documents/blob/master/Samples/Twitter.API/Twitter.fs#L183 )的别名。
尽管在工具提示中它显示为JsonProvider<...>.DomainTypes.Url
,但您必须使用类型别名TwitterTypes.SearchTweets.DomainTypes.Url