pl中的phpspec标量值

Question

我试图使用带有标量值的let函数.我的问题是价格是双倍的,我预计是5.

function let(Buyable $buyable, $price, $discount)
{
    $buyable->getPrice()->willReturn($price);
    $this->beConstructedWith($buyable, $discount);
}

function it_returns_the_same_price_if_discount_is_zero($price = 5, $discount = 0) {
    $this->getDiscountPrice()->shouldReturn(5);
}

错误:

? it returns the same price if discount is zero
expected [integer:5], but got [obj:Double\stdClass\P14]

有没有办法使用let函数注入5？

Answer 1

在PhpSpec中,无论参数是什么let(),letgo()或者it_*()方法都是测试双.它并不意味着与标量一起使用.

PhpSpec使用反射从类型提示或@param注释中获取类型.然后它创建一个带有预言的虚假对象并将其注入方法中.如果找不到类型,就会创建一个假的\stdClass. Double\stdClass\P14与double类型无关.这是一个双倍的考验.

您的规格可能如下:

private $price = 5;

function let(Buyable $buyable)
{
    $buyable->getPrice()->willReturn($this->price);

    $this->beConstructedWith($buyable, 0);
}

function it_returns_the_same_price_if_discount_is_zero() 
{
    $this->getDiscountPrice()->shouldReturn($this->price);
}

虽然我更愿意包含与当前示例相关的所有内容:

function let(Buyable $buyable)
{
    // default construction, for examples that don't care how the object is created
    $this->beConstructedWith($buyable, 0);
}

function it_returns_the_same_price_if_discount_is_zero(Buyable $buyable) 
{
    // this is repeated to indicate it's important for the example
    $this->beConstructedWith($buyable, 0);

    $buyable->getPrice()->willReturn(5);

    $this->getDiscountPrice()->shouldReturn(5);
}