pie*_*ard 8 lucene elasticsearch
我最近开始使用ElasticSearch.我尝试完成一些用例.其中一个我有问题.
我用一些用户的全名索引了一些用户(例如"Jean-Paul Gautier","Jean De La Fontaine").
我试图让所有的全名响应一些查询.
例如,我希望100个最常用的全名由"J"开始
{
"query": {
"query_string" : { "query": "full_name:J*" } }
},
"facets":{
"name":{
"terms":{
"field": "full_name",
"size":100
}
}
}
}
Run Code Online (Sandbox Code Playgroud)
我得到的结果是全名:"Jean","Paul","Gautier","De","La","Fontaine".
如何获得"Jean-Paul Gautier"和"Jean De La Fontaine"(所有full_name值由'J'乞讨)?"post_filter"选项不是这样做的,它只限制上面这个子集.
谢谢
Slo*_*ens 13
您只需"index": "not_analyzed"在该字段上设置,您就可以在您的方面获得完整的,未修改的字段值.
通常,有一个版本的字段没有被分析(用于分面)而另一个版本(用于搜索)是很好的.该"multi_field"字段类型是对这项有益的.
所以在这种情况下,我可以定义一个映射如下:
curl -XPUT "http://localhost:9200/test_index/" -d'
{
"mappings": {
"people": {
"properties": {
"full_name": {
"type": "multi_field",
"fields": {
"untouched": {
"type": "string",
"index": "not_analyzed"
},
"full_name": {
"type": "string"
}
}
}
}
}
}
}'
Run Code Online (Sandbox Code Playgroud)
这里我们有两个子字段.与父项同名的那个将是默认值,因此如果您搜索该"full_name"字段,Elasticsearch将实际使用"full_name.full_name"."full_name.untouched"将为您提供您想要的方面结果.
接下来我添加两个文件:
curl -XPUT "http://localhost:9200/test_index/people/1" -d'
{
"full_name": "Jean-Paul Gautier"
}'
curl -XPUT "http://localhost:9200/test_index/people/2" -d'
{
"full_name": "Jean De La Fontaine"
}'
Run Code Online (Sandbox Code Playgroud)
然后我可以在每个字段上查看返回的内容:
curl -XPOST "http://localhost:9200/test_index/_search" -d'
{
"size": 0,
"facets": {
"name_terms": {
"terms": {
"field": "full_name"
}
},
"name_untouched": {
"terms": {
"field": "full_name.untouched",
"size": 100
}
}
}
}'
Run Code Online (Sandbox Code Playgroud)
我回过头来看:
{
"took": 1,
"timed_out": false,
"_shards": {
"total": 1,
"successful": 1,
"failed": 0
},
"hits": {
"total": 2,
"max_score": 0,
"hits": []
},
"facets": {
"name_terms": {
"_type": "terms",
"missing": 0,
"total": 7,
"other": 0,
"terms": [
{
"term": "jean",
"count": 2
},
{
"term": "paul",
"count": 1
},
{
"term": "la",
"count": 1
},
{
"term": "gautier",
"count": 1
},
{
"term": "fontaine",
"count": 1
},
{
"term": "de",
"count": 1
}
]
},
"name_untouched": {
"_type": "terms",
"missing": 0,
"total": 2,
"other": 0,
"terms": [
{
"term": "Jean-Paul Gautier",
"count": 1
},
{
"term": "Jean De La Fontaine",
"count": 1
}
]
}
}
}
Run Code Online (Sandbox Code Playgroud)
如您所见,分析字段返回单字,低字符标记(当您未指定分析器时,使用标准分析器),未分析的子字段返回未修改的原始文本.
这是一个可以玩的可运行的例子:http: //sense.qbox.io/gist/7abc063e2611846011dd874648fd1b77450b19a5
| 归档时间: |
|
| 查看次数: |
3398 次 |
| 最近记录: |