如何格式化GPS经度和纬度？

Question

在android(java)中,当你使用函数getlatitude()等获得当前纬度和经度时,你得到十进制格式的坐标:

纬度:24.3454523经度:10.123450

我想把它变成度数和小数分钟看起来像这样:

纬度:40°42'51"N经度:74°00'21"W

Answer 1

从小数转换到度数你可以做如下

String strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_DEGREES);
String strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_DEGREES);

参考是android开发者网站.

编辑

我尝试了以下内容并获得输出:

strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_DEGREES);
strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_DEGREES);

OUTPUT : Long: 73.16584: Lat: 22.29924

strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_SECONDS);
strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_SECONDS);

OUTPUT : Long: 73:9:57.03876: Lat: 22:17:57.26472

strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_MINUTES);
strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_MINUTES);

OUTPUT : Long: 73:9.95065: Lat: 22:17.95441

根据您的要求尝试不同的选项

Answer 2

正如已经提到的，需要一些字符串操作。我创建了以下帮助程序类，它将位置转换为 DMS 格式并允许指定秒的小数位：

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import android.location.Location;\nimport android.support.annotation.NonNull;\n\npublic class LocationConverter {\n\n    public static String getLatitudeAsDMS(Location location, int decimalPlace){\n        String strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_SECONDS);\n        strLatitude = replaceDelimiters(strLatitude, decimalPlace);\n        strLatitude = strLatitude + " N";\n        return strLatitude;\n    }\n\n    public static String getLongitudeAsDMS(Location location, int decimalPlace){\n        String strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_SECONDS);\n        strLongitude = replaceDelimiters(strLongitude, decimalPlace);\n        strLongitude = strLongitude + " W";\n        return strLongitude;\n    }\n\n    @NonNull\n    private static String replaceDelimiters(String str, int decimalPlace) {\n        str = str.replaceFirst(":", "\xc2\xb0");\n        str = str.replaceFirst(":", "\'");\n        int pointIndex = str.indexOf(".");\n        int endIndex = pointIndex + 1 + decimalPlace;\n        if(endIndex < str.length()) {\n            str = str.substring(0, endIndex);\n        }\n        str = str + "\\"";\n        return str;\n    }\n}\n

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Answer 3

这是 Kotlin 版本，改编自 Martin Weber 的回答。它还设置正确的半球；N、S、W 或 E

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object LocationConverter {\n\n    fun latitudeAsDMS(latitude: Double, decimalPlace: Int): String {\n        val direction = if (latitude > 0) "N" else "S"\n        var strLatitude = Location.convert(latitude.absoluteValue, Location.FORMAT_SECONDS)\n        strLatitude = replaceDelimiters(strLatitude, decimalPlace)\n        strLatitude += " $direction"\n        return strLatitude\n    }\n\n    fun longitudeAsDMS(longitude: Double, decimalPlace: Int): String {\n        val direction = if (longitude > 0) "W" else "E"\n        var strLongitude = Location.convert(longitude.absoluteValue, Location.FORMAT_SECONDS)\n        strLongitude = replaceDelimiters(strLongitude, decimalPlace)\n        strLongitude += " $direction"\n        return strLongitude\n    }\n\n    private fun replaceDelimiters(str: String, decimalPlace: Int): String {\n        var str = str\n        str = str.replaceFirst(":".toRegex(), "\xc2\xb0")\n        str = str.replaceFirst(":".toRegex(), "\'")\n        val pointIndex = str.indexOf(".")\n        val endIndex = pointIndex + 1 + decimalPlace\n        if (endIndex < str.length) {\n            str = str.substring(0, endIndex)\n        }\n        str += "\\""\n        return str\n    }\n}\n

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Answer 4

应该是一些数学：

(int)37.33168                => 37

37.33168 % 1 = 0.33168
0.33168 * 60 = 19.905        => 19

19.905 % 1 = 0.905    
0.905 * 60                   => 54

与-122相同（如果为负值，则添加360）

编辑：可能有一些我不知道的API。

引用来源： 如何从android中的纬度值中找到度？

将纬度和经度值（度）转换为Double。爪哇