通过Android中的HTTP put请求将JSON发送到服务器

Question

如何将给定的json包装到字符串并通过Http put请求将其发送到服务器？

这就是我的json的样子.

    {
    "version": "1.0.0",
    "datastreams": [
        {
            "id": "example",
            "current_value": "333"
        },
        {
            "id": "key",
            "current_value": "value"
        },
        {
            "id": "datastream",
            "current_value": "1337"
        }
    ]
}

上面是我的json数组.

下面是我编写代码的方法,但它不起作用

        protected String doInBackground(Void... params) {
            String text = null;
            try {
                JSONObject child1 = new JSONObject();
                try{
                    child1.put("id", "LED");
                    child1.put("current_value", "0");


                } catch (JSONException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }


                JSONArray jsonArray = new JSONArray();

                jsonArray.put(child1);

                JSONObject datastreams = new JSONObject();
                datastreams.put("datastreams", jsonArray);  

                JSONObject version = new JSONObject();
                version.put("version", "1.0.0");
                version.put("version", datastreams);


             HttpClient httpClient = new DefaultHttpClient();
             HttpContext localContext = new BasicHttpContext();
             HttpPut put = new HttpPut("url");
             put.addHeader("X-Apikey","");
             StringEntity se = new StringEntity( version.toString());  
             se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));

             put.addHeader("Accept", "application/json");
             put.addHeader("Content-type", "application/json");
             put.setEntity(se);


             try{

                   HttpResponse response = httpClient.execute(put, localContext);
                   HttpEntity entity = response.getEntity();
                   text = getASCIIContentFromEntity(entity);
             }
              catch (Exception e) {
                 return e.getLocalizedMessage();
             }


        }catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (UnsupportedEncodingException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }
            return text;
        }

请帮忙

Answer 1

这是一个样本。

    JSONObject Parent = new JSONObject();
    JSONArray array = new JSONArray();

    for (int i = 0 ; i < datastreamList.size() ; i++)
    {
        JSONObject jsonObj = new JSONObject();

        jsonObj.put("id", datastreamList.get(i).GetId());
        jsonObj.put("current_value", datastreamList.get(i).GetCurrentValue());
        array.put(jsonObj);
    }       
    Parent.put("datastreams", array);       
    Parent.put("version", version);

并发送：

    HttpClient client = new DefaultHttpClient();
    HttpPost post = new HttpPost(url);
    StringEntity se = new StringEntity( Parent.toString());  
    se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
    post.setHeader("Accept", "application/json");
    post.setHeader("Content-type", "application/json");
    post.setEntity(se);
    client.execute(post);

编辑

在此示例中datastreamList，for 语句中使用的是一个列表，对于要发送到服务器的所有值，您必须拥有该列表（具有 2 个属性的一个类的一个列表， id和value），实际上我认为您有两个类，如下所示：

class A {

List<Datastreams> datastreamList
String version;
//get
//set
}

class Datastreams {

String id;
String current_value; // or int
//get
//set
}

并且在您的代码中，您必须有一个 A 类对象想要发送到服务器，因此您可以使用第一部分将您的映射object到json.