Squ*_*Pie 7 python raspberry-pi
我正在尝试使用我的Raspberry Pi创建一个python类来控制步进电机.它主要工作,但是'__getitem__'每当我将列表定义为类变量时,我继续得到一个"'instancemethod'对象没有属性错误.错误消息列出这段代码作为罪魁祸首但是我看不出它有什么问题如果seq [self.StepCounter] [pin]!= 0:.如果我将其定义为实例变量或全局变量,它将起作用.这是我的代码:导入RPi.GPIO作为GPIO导入时间debug = True
class stepper:
clockwise = []
clockwise = range(0,4)
clockwise[0] = [1,0,0,0]
clockwise[1] = [0,1,0,0]
clockwise[2] = [0,0,1,0]
clockwise[3] = [0,0,0,1]
def __init__(self,pin1,pin2,pin3,pin4):
GPIO.setwarnings(False)
GPIO.setmode(GPIO.BCM)
self.pin1 = pin1
self.pin2 = pin2
self.pin3 = pin3
self.pin4 = pin4
self.StepCounter = 0
self.pinarray = [pin1,pin2,pin3,pin4]
for pin in self.pinarray:
if debug == True:
print "Setup pin " + str(pin)
GPIO.setup(pin,GPIO.OUT)
GPIO.output(pin, False)
self.stepNum = 512.0
self.coilNum = 4.0
def setup(self,stepNum,coilNum):
self.stepNum = float(stepNum)
self.coilNum = float(coilNum)
self.partNum = self.coilNum * self.stepNum
def clockwise(self,speed):
seq = stepper.clockwise
self.WaitTime = (1.0 / (self.stepNum * self.coilNum)) * speed
for pin in range(0, 4):
xpin = self.pinarray[pin]
if seq[self.StepCounter][pin]!=0:
GPIO.output(xpin, True)
else:
GPIO.output(xpin, False)
self.StepCounter += 1
if (self.StepCounter==len(seq)):
self.StepCounter = 0
if (self.StepCounter<0):
self.StepCounter = len(seq)
time.sleep(self.WaitTime)
print "Adding Motor Instance"
motor = stepper(24,25,8,7)
print "Spinning Motor"
while "True":
motor.clockwise(5)
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请有人能告诉我它有什么问题并解释原因.谢谢
DSM*_*DSM 11
你没有发布完整的追溯,但我可以猜测:
def clockwise(self,speed):
seq = stepper.clockwise
self.WaitTime = (1.0 / (self.stepNum * self.coilNum)) * speed
for pin in range(0, 4):
xpin = self.pinarray[pin]
if seq[self.StepCounter][pin]!=0:
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您设置的seq等于stepper.clockwise第一行的方法.然后几行后你尝试索引它:seq[self.StepCounter].但是获取方法的self.StepCounter第th个元素意味着什么?
没什么,因为:
'instancemethod' object has no attribute '__getitem__'
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您不应该同时使用clockwise它们作为列表的名称和方法的名称; 只有最后执行的定义才会成立,所以当你到达时seq = stepper.clockwise,它就是方法,而不是列表.
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