如何在DB中检查模型的存在?在Yii 1版本中它是如此
User::model()->exist()
ipp*_*ppi 48
在Yii2中,您可以添加exists()到您的查询链:
User::find()
->where( [ 'id' => 1 ] )
->exists();
Run Code Online (Sandbox Code Playgroud)
(生成的SQL如下所示:SELECT 1 FROM `tbl_user` WHERE `id`=1.)
/**
* Returns a value indicating whether the query result contains any row of data.
* @param Connection $db the database connection used to generate the SQL statement.
* If this parameter is not given, the `db` application component will be used.
* @return bool whether the query result contains any row of data.
*/
public function exists($db = null)
{
if ($this->emulateExecution) {
return false;
}
$command = $this->createCommand($db);
$params = $command->params;
$command->setSql($command->db->getQueryBuilder()->selectExists($command->getSql()));
$command->bindValues($params);
return (bool) $command->queryScalar();
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
31761 次 |
| 最近记录: |