使用c#的XML到CSV而不使用xslt

Question

我一直在网上搜索,我假设有一个必须在我面前需要这个并且做得更好,对于xml到csv转换器.我有一个非常标准的xml如下:

<ArrayOfDealer xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
    <Dealer>
        <Cmf>76066699</Cmf>
        <DealerNumber/>
        <DealershipName>BROWARD MOTORSPORTS - WPB</DealershipName>
    </Dealer>
    <Dealer>
        <Cmf>76071027</Cmf>
        <DealerNumber/>
        <DealershipName>BROWARD MOTORSPORTS OF FT LAUDERDALE LLC</DealershipName>
    </Dealer>
    <Dealer>
        <Cmf>76014750</Cmf>
        <DealerNumber/>
        <DealershipName>Jet Ski of Miami</DealershipName>
    </Dealer>
    <Dealer>
        <Cmf>76066987</Cmf>
        <DealerNumber/>
        <DealershipName>BROWARD MOTORSPORTS - Davie</DealershipName>
    </Dealer>
</ArrayOfDealer>

我想把它解析成类似的东西

cmf      dealernumber    dealershipname
76066699                 BROWARD MOTORSPORTS - WPB
76014750                 Jet Ski of Miami
76066987                 BROWARD MOTORSPORTS - Davie

XML来自一个我存储为字符串的api.

思考？

编辑:为了澄清,我知道结构将如上所述,没有进一步的节点嵌套,但实际的标签名称可以非常.

Answer 1

这样的事情会得到你所需要的:

Func<string, string> csvFormat =
    t => String.Format("\"{0}\"", t.Replace("\"", "\"\""));

var xml = XDocument.Parse(/* xml text here */);

Func<XDocument, IEnumerable<string>> getFields =
    xd =>
        xd
            .Descendants("Dealer")
            .SelectMany(d => d.Elements())
            .Select(e => e.Name.ToString())
            .Distinct();

var headers =
    String.Join(",",
        getFields(xml)
            .Select(f => csvFormat(f)));

var query =
    from dealer in xml.Descendants("Dealer")
    select string.Join(",",
        getFields(xml)
            .Select(f => dealer.Elements(f).Any()
                ? dealer.Element(f).Value
                : "")
            .Select(x => csvFormat(x)));

var csv =
    String.Join(Environment.NewLine,
        new [] { headers }.Concat(query));

这仍假设<ArrayOfDealer><Dealer>结构相同,但下面的字段可能会改变.