使用Play框架在View中格式化ValidationError

Mik*_*ike 2 java scala validationerror playframework playframework-2.0

我无法从我的视图中访问ValidationError消息.我设法在我的视图中获得的唯一输出是:

[ValidationError(username,Too short, sorry ;),[6])]
[ValidationError(password,Confirmation password doesn't match,[])]
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我只想输出错误消息:"太短,抱歉;)"和"确认密码不匹配".

我找到的解决方法是从表单中调用特定字段,然后访问错误消息:

@form("password").error.map(_.message).getOrElse("")
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谢谢,

我的观点register.scala.html:

@if(form.hasErrors) {
<div class="form-group">
    <div class="alert alert-danger col-lg-6 text-center">
       @for((key, vamlue) <- form.errors){
         @value<br />
       }
   </div>
</div>
}
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我的控制器:

public static Result registerSubmit(){
        Form<User> registerForm = form(User.class).bindFromRequest();
        String passwordConfirmation = registerForm.field("passwordConfirmation").value();

        if(!registerForm.field("password").valueOr("").equals(passwordConfirmation)){
            ValidationError e = new ValidationError("password", "Confirmation password doesn't match");
            registerForm.reject(e);
        }

        if (registerForm.hasErrors()){
            // Handle Error
            return badRequest(register.render(registerForm));
        } else {
            // Check if all data are fine    
            // TODO : Redirect to Login Page
            return ok(register.render(registerForm));
        }
    }
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最后是模型User.java:

@Required
@MinLength(6)
String username;

@Required
@Email
String email;

@Required
@MinLength(6)
String password;
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avi*_*vik 5

听起来您想要收集所有表单错误并将其显示在表单的顶部.我认为这是您希望在HTML模板中使用的代码块

@if(form.hasErrors) {
  <div class="form-group">
    <div class="alert alert-danger col-lg-6 text-center">
      @for(entry <- form.errors.entrySet){
        @for(error <- entry.getValue){
          @error.message <br/>
        }
      }
    </div>
  </div>
}
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如果将form.errors映射从Java映射转换为Scala映射,则可以使代码块比嵌套的for循环更简洁,但这应该可以完成.