C++接口继承

Adi*_*be7 1 c++ inheritance interface

我怎样才能在C++中进行这种推导?(当前示例不起作用)

  struct IB
    {

    };

    struct IDerivedB : public IB
    {

    };

    struct IA
    {
    public:
        virtual IB Foo(const string& type) = 0;
    };

    struct IDerivedA : public IA
    {
    public:
        virtual IDerivedB Foo(const string& type) override = 0;
    };
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谢谢!

yur*_*hek 6

返回类型协方差仅适用于指针和引用,这应该工作:

struct IB
{

};

struct IDerivedB : public IB
{

};

struct IA
{
public:
    virtual IB* BuildPresenter(const string& type) = 0;
};

struct IDerivedA : public IA
{
public:
    virtual IDerivedB* BuildPresenter(const string& type) override = 0;
};
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