如何以Pythonic方式将此元组列表转换为此dict？

Question

我有一个元组列表

tuplist = [('person', u'English : 1, 2, 3 ; Dutch : 5, 6, 7'), ('home', u'English : 8, 9, 10; Dutch: 11, 12, 13')]

我想将此转换为这个特定的词典

{'person': {u'Dutch': [u'5', u'6', u'7'], u'English': [u'1', u'2', u'3']}, 'home': {u'Dutch': [u'11', u'12', u'13'], u'English': [u'8', u'9', u'10']}}

目前我这个:

dic = dict(tuplist)
final_dic = {}
for x in dic:
    str = dic[x]
    list1 = [y.strip() for y in str.split(';')]
    subdict = {}
    for z in list1:
        list2 = [y.strip() for y in z.split(':')]
        subdict[list2[0]] = [y.strip() for y in list2[1].split(',')]
    final_dic[x] = subdict

但我想把它重写为Pythonic.有人有想法吗？

Answer 1

您可以嵌套一组字典和列表推导:

{k: {l.strip(): [n.strip() for n in nums.split(',')] 
     for i in v.split(';') 
     for l, nums in (i.split(':', 1),)}
 for k, v in tuplist}

这是一个很大的口,所以最好将语言字典拆分成一个生成器:

def language_values(line):
    for entry in line.split(';'):
        lang, nums = entry.split(':', 1)
        yield lang.strip(), [n.strip() for n in nums.split(',')]

{k: dict(language_values(v)) for k, v in tuplist}

任何一个产生所需的输出:

>>> {k: {l.strip(): [n.strip() for n in nums.split(',')] 
...      for i in v.split(';') 
...      for l, nums in (i.split(':', 1),)}
...  for k, v in tuplist}
{'person': {u'Dutch': [u'5', u'6', u'7'], u'English': [u'1', u'2', u'3']}, 'home': {u'Dutch': [u'11', u'12', u'13'], u'English': [u'8', u'9', u'10']}}
>>> def language_values(line):
...     for entry in line.split(';'):
...         lang, nums = entry.split(':', 1)
...         yield lang.strip(), [n.strip() for n in nums.split(',')]
... 
>>> {k: dict(language_values(v)) for k, v in tuplist}
{'person': {u'Dutch': [u'5', u'6', u'7'], u'English': [u'1', u'2', u'3']}, 'home': {u'Dutch': [u'11', u'12', u'13'], u'English': [u'8', u'9', u'10']}}