Bash脚本倒计时器需要检测任何键才能继续

Question

我需要在倒数计时器循环中收听任何按键.如果按下任何键,则倒数计时器应该突破它的循环.这主要是有效的,除了输入键只是让倒数计时器更快.

#!/bin/bash
for (( i=30; i>0; i--)); do
    printf "\rStarting script in $i seconds.  Hit any key to continue."
    read -s -n 1 -t 1 key
    if [[ $key ]]
    then
        break
    fi
done
echo "Resume script"

我似乎无法找到任何在线任何位置检测输入密钥的示例.

Answer 1

我认为根据返回代码read,有一个解决这个问题的方法.从man页面read,

The return code is zero, unless end-of-file is encountered, read times out,
or an invalid file descriptor is supplied as the argument to -u.

超时的返回码似乎是142[在Fedora 16中验证]

所以,脚本可以修改为,

#!/bin/bash
for (( i=30; i>0; i--)); do
    printf "\rStarting script in $i seconds.  Hit any key to continue."
    read -s -n 1 -t 1 key
    if [ $? -eq 0 ]
    then
        break
    fi
done
echo "Resume script"