Md *_*ain 10 javascript ajax jquery json
我不是jQuery的专家,认为我更新鲜.这是我的代码,其中一个不负责Request Body提交的jQuery JSON数据.
<!doctype html>
<html lang="en">
<head>
<title>jQuery Data submitted by JSON Body Request</title>
<script type="text/javascript" src="jquery-1.3.2.js"></script>
<script type="text/javascript">
$.ajax({
url : "/",
type: "POST",
data: [
{id: 1, name: "Shahed"},
{id: 2, name: "Hossain"}
],
contentType: "application/json; charset=utf-8",
dataType : "json",
success : function(){
console.log("Pure jQuery Pure JS object");
}
});
</script>
</head>
<body>
<p>
Example of submission JS Object by JSON Body Request<br/>
Its could submitted mass amount of data by Message body<br/>
It's secured and faster than any data submission .
</p>
</body>
</html>
Post Source出现:
Shahed=undefined&Hossain=undefined
但是期望的Post Source是:
[{"id":1,"name":"Shahed"},{"id":2,"name":"Hossain"}]
如何为每个请求主体获取所需的帖子来源？
Md *_*ain 17
这是您想要的输出的正确代码.
$.ajax({
url : "/",
type: "POST",
data: JSON.stringify([
{id: 1, name: "Shahed"},
{id: 2, name: "Hossain"}
]),
contentType: "application/json; charset=utf-8",
dataType : "json",
success : function(){
console.log("Pure jQuery Pure JS object");
}
});
您必须将JS对象转换为String,并且JSON.stringify(JSObject)是负责该方法的方法.
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